This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: hiarker (srh959) – homework 01 – Turner – (58220) 1 This printout should have 12 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A block of material has dimensions 3 . 6 cm by 6 . 5 cm by 3 . 1 cm. Its mass is 614 g. What is the density? Correct answer: 8 . 4643 g / cm 3 . Explanation: Let : ℓ = 6 . 5 cm , w = 3 . 6 cm , h = 3 . 1 cm , and m = 614 g . Density is mass per unit volume, so ρ = m V = m ℓ w h = 614 g (6 . 5 cm)(3 . 6 cm)(3 . 1 cm) = 8 . 4643 g / cm 3 . 002 10.0 points Convert an acceleration of 2 . 9 mi / h / s to m / s 2 . Correct answer: 1 . 29614 m / s 2 . Explanation: Let : a = 2 . 9 mi / h / s . a = 2 . 9 mi h · s · 1 . 609 km 1 mi · 1000 m 1 km · 1 h 3600 s = 1 . 29614 m / s 2 . 003 10.0 points Convert 41 ◦ to radians. Correct answer: 0 . 715585 rad. Explanation: Since π rad = 180 ◦ , 41 ◦ parenleftbigg π rad 180 ◦ parenrightbigg = . 715585 rad . 004 10.0 points Find the area of a rectangular building lot that is 145 ft by 110 ft. Correct answer: 1481 . 8 m 2 . Explanation: Let : ℓ = 145 ft and w = 110 ft . A = ℓ w = (145 ft) (110 ft) parenleftbigg 12 in 1 ft parenrightbigg 2 × parenleftbigg 2 . 54 cm 1 in parenrightbigg 2 parenleftbigg 1 m 100 cm parenrightbigg 2 = 1481 . 8 m 2 . Alternate conversions factors are 1 m = 3.281 ft and 0.3048 m = 1 ft, which would also have to be squared....
View
Full
Document
This note was uploaded on 04/23/2010 for the course PHY 303K taught by Professor Nui during the Spring '09 term at University of TexasTyler.
 Spring '09
 NUI
 Physics, Work

Click to edit the document details