HW1_Solutions

# HW1_Solutions - hiarker (srh959) – homework 01 – Turner...

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Unformatted text preview: hiarker (srh959) – homework 01 – Turner – (58220) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points A block of material has dimensions 3 . 6 cm by 6 . 5 cm by 3 . 1 cm. Its mass is 614 g. What is the density? Correct answer: 8 . 4643 g / cm 3 . Explanation: Let : ℓ = 6 . 5 cm , w = 3 . 6 cm , h = 3 . 1 cm , and m = 614 g . Density is mass per unit volume, so ρ = m V = m ℓ w h = 614 g (6 . 5 cm)(3 . 6 cm)(3 . 1 cm) = 8 . 4643 g / cm 3 . 002 10.0 points Convert an acceleration of 2 . 9 mi / h / s to m / s 2 . Correct answer: 1 . 29614 m / s 2 . Explanation: Let : a = 2 . 9 mi / h / s . a = 2 . 9 mi h · s · 1 . 609 km 1 mi · 1000 m 1 km · 1 h 3600 s = 1 . 29614 m / s 2 . 003 10.0 points Convert 41 ◦ to radians. Correct answer: 0 . 715585 rad. Explanation: Since π rad = 180 ◦ , 41 ◦ parenleftbigg π rad 180 ◦ parenrightbigg = . 715585 rad . 004 10.0 points Find the area of a rectangular building lot that is 145 ft by 110 ft. Correct answer: 1481 . 8 m 2 . Explanation: Let : ℓ = 145 ft and w = 110 ft . A = ℓ w = (145 ft) (110 ft) parenleftbigg 12 in 1 ft parenrightbigg 2 × parenleftbigg 2 . 54 cm 1 in parenrightbigg 2 parenleftbigg 1 m 100 cm parenrightbigg 2 = 1481 . 8 m 2 . Alternate conversions factors are 1 m = 3.281 ft and 0.3048 m = 1 ft, which would also have to be squared....
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## This note was uploaded on 04/23/2010 for the course PHY 303K taught by Professor Nui during the Spring '09 term at University of Texas-Tyler.

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HW1_Solutions - hiarker (srh959) – homework 01 – Turner...

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