HW26_Solutions

# HW26_Solutions - hiarker(srh959 – homework 26 – Turner...

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Unformatted text preview: hiarker (srh959) – homework 26 – Turner – (58220) 1 This print-out should have 7 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points There is a moon orbiting an Earth-like planet. The mass of the moon is 1 . 58 × 10 22 kg, the center-to-center separation of the planet and the moon is 5 . 42 × 10 5 km, the orbital period of the moon is 21 . 7 days, and the radius of the moon is 1710 km. What is the angular momentum of the moon about the planet? Correct answer: 1 . 55547 × 10 34 kg m 2 / s. Explanation: The angular speed ω in radians per unit time, for a complete circle is ω = 2 π T . Angular momentum L is L = m v r = m r 2 ω = 2 π m r 2 T = 2 π (1 . 58 × 10 22 kg) × bracketleftbigg (5 . 42 × 10 5 km) 1000 m 1 km bracketrightbigg 2 (21 . 7 days) parenleftbigg 24 hr 1 day parenrightbigg = 1 . 55547 × 10 34 kg m 2 / s . 002 (part 1 of 3) 10.0 points A 3 kg bicycle wheel rotating at a 2294 rev / min angular velocity has its shaft supported on one side, as shown in the fig- ure. The wheel is a hoop of radius 0 . 6 m, and its shaft is horizontal. The distance from the center of the wheel to the pivot point is 0 . 4 m....
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HW26_Solutions - hiarker(srh959 – homework 26 – Turner...

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