Quiz2-2007-102

Quiz2-2007-102 - Fy = F cos ϑ = cos ϑ = x 2 Q2 cos ϑ...

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Unformatted text preview: Fy = F cos ϑ = cos ϑ = x 2 Q2 cos ϑ 4πε x 2 + d 2 1 x + d2 Q2 x Fy = = Mg 4πε (x 2 + d 2 )3 / 2 d Fy = 0 dx (x + d ) 2 (x + d ) Q (x + d ) (d − 2 x ) ⋅ =0 4πε (x + d ) 3/ 2 2 2 Q 2 (x + d ) ⋅ 4πε 2 2 −x3 2 2 2 1/ 2 2x 23 2 =0 2 1/ 2 2 2 23 d 2 − 2x2 = 0 d x= 2 Fy = Mg Q = Mg ⋅ 3/ 2 4πε ⎛ d 2 ⎞ 2 ⎜ ⎟ ⎜ 2 +d ⎟ ⎠ ⎝ Q = d 6 3Mgπε 2 d 2 ...
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This note was uploaded on 04/23/2010 for the course -- -- taught by Professor -- during the Spring '10 term at Bilkent University.

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