Quiz16-2007-102

Quiz16-2007-102 - a ρ F = iL × B B= µ0i 2πd µi F = iL 0 2πd 2 i Lµ0 F= 2πd F i 2 µ0 = L 2πd B1 cos θ B2 sin α = Beffective b µ0i 2πr

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Unformatted text preview: a) ρ F = iL × B B= µ0i 2πd µi F = iL 0 2πd 2 i Lµ0 F= 2πd F i 2 µ0 = L 2πd B1 cos θ + B2 sin α = Beffective b) µ0i 2πr µi B2 = 0 2πr B1 = d2 r= z + 4 2 Beff = µ0i 2 2 ⋅ 2 z d z+ 4 2 + µ 0i d 2π z + 4 2 2 ⋅ z d2 z+ 4 2 Beff d 2π z + 4 µ0iz = ⎛ d2 ⎞ π ⎜ z2 + ⎟ ⎜ 4⎟ ⎠ ⎝ d Beff = 0 dz ⎛d2 2⎞ ⎜ ⎟ ⎜ 4 + z ⎟ − 2 z. z µi ⎠ 0= 0 ⋅⎝ 2 2 π ⎛d 2⎞ ⎜ ⎟ ⎜ 4 +z ⎟ ⎠ ⎝ d2 − z2 = 0 4 d z=± 2 This is where B becomes maximum on the z axis, above and below the xy-plane. B1 is magnetic field at P due to wire 1, and B2 is that due to wire 2. ...
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This note was uploaded on 04/23/2010 for the course -- -- taught by Professor -- during the Spring '10 term at Bilkent University.

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Quiz16-2007-102 - a ρ F = iL × B B= µ0i 2πd µi F = iL 0 2πd 2 i Lµ0 F= 2πd F i 2 µ0 = L 2πd B1 cos θ B2 sin α = Beffective b µ0i 2πr

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