test2 - ITIHH—dd—dlfllflb 115“ 115] LIITIL. L1U1L...

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Unformatted text preview: ITIHH—dd—dlfllflb 115“ 115] LIITIL. L1U1L I:NL:I1N|:I:H1NL:I D'KJ titid 4'Kt14 1" . [rill/[filth ENGR 2200- Intermediate Strength of Materials WJ. Likes Test #2 Winter 2006 ENGR 2200 a Test #2 (100 points) March 20, 2006 Student Name (7 DL—W! M? Student ID My signature verifies that I have completed these exam questions independently and without the aid of additional notes, equations, or materials not provided by the instructor. I have not received assistance from other students. I understand that the use of prohibited items or assistance is considered an unfair advantage and will be documented and treated as academic dishonesty. Signature Equations for use: Me 1 1 2 33A =— 1 m—bh3 S:- ‘=—-—~— I: Hate!2 Jinan I rec: tan gig c y A Z ( ) l E M m- = £13: a = —2 ax = 31: — fl (consider signs) ax = —M§l + yz (consider signs) ,0 E! E l A 1 I: I), V,3 - VA 2 — J-wdx (change in shear from A to B under distributed load) M ,3 HM) = J.de (change in moment from A to B is area under shear diagram) |M Jail max I 5.: mm 1/5 MHR-EE-EE’IEE 1E1=1IZ1 LIMC CIUIL ENGINEERING 573 882 4784 REE/[215 ENGR 2200— Intermediate Strength ofMarerials WJ. Likes Tee't #2 Winter 2006 Question 1. (30 points). The beam shown below is made of nylon for which the allowable stress is 24 MP3. in tension and 30 MPa in compressiou. Determine the largest couple M that can be applied to the beam. 3 1. , a}... M7- : fli(4n)l|5)+ (401515) '* 1:. T12 l “260 + 15000 = 2925‘" mm s 1 g - 3' 1" : '5') *‘ (20]151’9) 4,: 31% me fix; 4‘ wow __ wazfmq a 4 . ff ., rle.-F;1= Ella-Iguan ‘5 ELBFP; X“) m @ _, ,7; =125m '+ 0.0125m 1 .EWS'M @ 15m; devil“) (T’l’). a: 50 gm LonPMWM (m): ‘0: -9 e1- l “3.3 M M‘afi' "Tb-H .- D.fll1;m a) h .. 6‘5» zax'oxbl'ngxm = lab-l N-M r""" 7' 0.0l7‘; MM 1' '1 Nrm 2/5 MFIR-EE-EE’IEIE: 18:12 LIME lCILI'IL ENGINEERING 573 882 4784 HEB/[35 EN GR 2200- Intermediate Strength of Materials W1 Likes Test #2 Winter 2006 Question 2. (30 points). A steel bar (E; = 210 GPa) and aluminum bar (E, = 70 GPa) are bonded together to form the composite bar shown. If a moment M = 60 him is applied about the horizontal axis, determine: (a) the maximum axial stress in the aluminum; (b) the maximum axial stress in the steel. TM AWWN ’72? AM‘ 3" GM " E3 ‘ fl 3 “T. "g; "I: *1 aw—g‘z‘” 3‘" 7.2:??? t a q r . ‘ .,; ", #7 ,‘5‘ mm ,.. I $47k +Ml 1 rilmja) + (711%123 *" ‘3’ ‘3 x” 3 “i 3 71L_ FL- 4’ :3 Kid" mm at” ‘1' a a 4 ED ,1; filsiz: )‘3,'5}23“(§wm I )339’25’s’0 rm 1 w t. “ W - "' 1 Lf 5 , D7 2 ‘13. 1C) at“ 1 WWW” tr: rataer M Lfgll Mm W) 3) (a - # {EDZDM2-31,IEOX:O I’m (c) (MIRA I: j: 1 } 5.5% m0 ems. : $1.1MTA 3/5 MHR-EE-EE’IEE 1E1=11 LIMC CIUIL ENGINEERING 573 882 4784 REM/[215 ENGR 220.5% Intermediate Slrmgt/t of Materials WJ. Likes Test #2 Winter 2006 Question 3. (40 points). A rectangular beam with width b = 0.1 m and height it is loaded as shown. (a) Draw and label the shear and bending moment diagrams. (b) If the allowable axial Stress is 120 MPa, determine the necessary height of the beam ()2). 24KN 24kN 24kN 24kN A it: in lE F is r H a M A I. a v 9*” ‘ A b = 0.1 m 0.75m 0.75m 0.75m 0.75m 0.75m * ae- éww if? E? a Lag-ID ; 9L, MO :U- A 2.4(0715) + Mayne) + qug)f1g) — Kala-"3‘39 * znlflens) -. o tab W l ‘52s: at?) T ’ \‘M._, M ‘r \ fl is M (2"; weyN‘th/Q Me 0 we H -. “WWW'W’” a 3- e ‘2 a new in WW9 HEEL") 1 fit? a: ems m 2.731303 A I 57.0% = ii? i/ a k1 s D. mag 4/5 888—28—2888 18: 1 1 Problem 4.109 Problem 4.110 or dim-Mud in any form or by any means, without fin: prior wnunn pcmxssiun of flu: publisher. or us: wanton pennincd by McGrawI-Iill LIIYIC I; I U I L ENGINEER I NC: 573 882 4784 F'.lZIS/IZIS 4.109 Knowing that the allowable stress in section ABD is 10 ksi, dam-nine the largest force P which canine applied to thb bracket shown. A 2: (1.2.1033): LOE m “.1:= LhCI-ZICD-fi" = 72.1 vidain u r; = £69.87: 0.45“ .14, e: 1+D-45"=2.‘f in. 'F’ "P Pee- +MIQ" "*3: “PK 6d: A a 2:: _ I (EHSXDHSJ _ ..2_ K: 17* f - ma * 72fi'flb'5 4”“ 0,8231% P: GMJL. an 4.110 Anofi‘seth mustbaimmduced into a soiid circularrodofdiamflerd. Knowingthatthemmdnmmstmsafierflxeoflnctisintrodumdmunnmmounds fimesthnsuessmthemdwhenitismaighgdmflmthemufihfithatmbe used. P Ear can'l'rt'w fioaAinj C54 = A3 _ _E Phc 6“ A + .I Far Eccm'l'n': fouling Give“ 6-2, I: for flack individunl course pmpmtion. If you an: a studmt using this Mnnual, you an: usmfi it wifimut pannisainn. TEITFIL F' . BS ...
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This note was uploaded on 04/03/2008 for the course CE ENGR 2200 taught by Professor Likos during the Spring '05 term at Missouri (Mizzou).

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test2 - ITIHH—dd—dlfllflb 115“ 115] LIITIL. L1U1L...

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