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Unformatted text preview: th—dti—dlﬂl/JD KIT: iiiEl L"'._. li_.1'~.x'1L I:NL'.I1N:I:H1NL'.I D'KJ title.” 4'Kti4 l" . Ell/Ell: ENGR 2200 Intermediate Strength ofMuterials WJ. Likes
Test #1 Fall 2005 ENGR 2200 — Test #1 (100 points) Student Name #50 LU'T'! mg Student ID My signature veriﬁes that l have completed these exam questions. independently and without the
aid of additional notes, equations, or materials not provided by the instructor. I have not received
assistance from other students. I understand that the use of prohibited items or assistance is
considered an unfair advantage and will be documented and treated as academic dishonesty. Signature Equations for use: i 2" TL
Chg anemia}: s E p ’r “ 1/6 th—dti—dlﬂlﬂb UT: DU LIITIL, L1U1L I:NL:I1N:I:H1NL:I D'KJ titid 4'Kt14 1" . Eld/ Ell: ENGR 2200~ Intermediate Strength ofMerert'els WJ. Likes
Test #1 Fall 2005 Question 1. (10 points). Sketch a typical o—e diagram for a ductile material (such as steel) when
subjected to axial loading in tension. You must label the axes and denote the location of the
following on the sketch: yield stress (o'y), ultimate stress (on), breaking stress (ob), Young‘s
modulus (E), the elastic behavior region, and the plastic behavior region. ELMhr. “Nai“ ‘5 Question 2. (5 points). A steel member is loaded in tension from point A to point B. Sketch the
expected stress—strain response if the member is then unloaded from point B back to o‘ = 0. “he Restit Milan/“"103 Questions 3 s 7 (True or False; circle the correct answer; 2 points each) 3. If the design factor of safety for a member is 3.0, the ultimate stress is 8 ksi, and the allowable
stress is 2.8 ksi, then this member is suitable for the design. p; g E: _ . ZBE .1; 3 (T ®
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4. Machines typically operate at stresses that result in plastic deformation. (T ®
5. Axial stress distribution in an eccentrically loaded compression member is uniform. (T® 6. Shear modulus describes the relationship between axial strain and lateral strain. (T 7. If a ductile material is loaded in tension, we expect some stretching before failure. @ F) 2/6 SEPEBEE’IES [37:58 LIMC CIUIL ENGINEERING 573 882 4784 HEB/[216 ENGR 2200— Intermediate Strength efMeterictls WJ. Likes
Test #1 F all 2005 Question 8 (25 points). Each of the four vertical links has an 8 X 36mm unifcnn rectangular
cross section and each of the four pins has a 164mm diameter. Determine the maximum value of
average normal stress in the links connecting (a) points 13 and D, and 03) points C and E. 0.4 m4
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Test #1 Fall 2005 Question 9 (25 points). The 40ﬁ long steel rails on a train track are laid with a small gap
between them to allow for thermal expansion. The coefﬁcient of thermal expansion for steel is on = 6.6 X 10“5 1/ c“F and E = 29 X 103 psi. The cross—sectional area of each rail is A = 5.10 ml. (3.) Determine the required gap 5 so that the rails just touch one another when the temperature is
increased from T1 = —20°F to T2 = 90°F. (.2
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g‘ : {£36qi (b) Using the gap from part (a), what would be the axial force in the rails if the temperature were
to rise from —20°F to l 10"}? ? 355;” 5 HO *L‘ZD); {EDUF
trite WWW. 6 : QMHCCTXL) : (es HELIIBDILiDDUZD : 0H: " 6D mmm m 42.5% eoMQMée'roA :59: Sf DLH  0343' = 9.06
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ENGR 2200 Intermediate Strength 0f Materials W1. LikOS
Fall 2005 Tesr #1 Question 10 (25 points). The torques shown are acting at points B, C, and D. If the shaft is made
of steel ((3 = 27 GPa), determine the angie of twist between (a) C and B, and (b) D and B. 3“ mm f
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Test #1 Fall 2005 Extra Credit (5 points). The change in diameter of a large steel bolt is carefully measured as the
nut is tightened. Knowing that E = 200 GPa and Poisson’s Ratio v = 0,29, determine the tensile force in the bolt if the diameter is observed to decrease by 13 X 10'6 m. ﬁnmﬁeﬁ ! (lie, mwa !e
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This note was uploaded on 04/03/2008 for the course CE ENGR 2200 taught by Professor Likos during the Spring '05 term at Missouri (Mizzou).
 Spring '05
 Likos

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