InClassActivity01-sol - Last Name Activity #01 (solutions)...

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ECSE-2660 Computer Architecture, Networks, & Operating Systems, Spring 2003 Page 1 of 4 Activity #01 (solutions) Last Name First Name Student ID Number 1.1 1.2 Total Grader Initials 50 points 50 points 100 points Morning Session Evening Session Activity 1.1 (First hour) A. (5 points) Administrative matters 1. (3 points) Click on course syllabus, and note the course pre-requisites. Check off the boxes that apply to you: I took ECSE 2610 (Computer Components and Operations) I took LITEC I took CSCI-2500 (Computer Organization) Other (please see course secretary immediately) Grading: 3pts for any answer, 0pts for no answer. 2. (2 points) Do you have a learning disability that your instructor should be aware of? Nope. Yes, I have one. Please contact the course secretary immediately for further guidance. Grading: 2pts for any answer, 0pts for no answer. B. (25 points) Recap of binary number representation Grading for all the questions below: 2pts for trying, 5pts for correct answer. 1. (5 points) 87 10 = 1010111 2 = 127 8 = 57 16 2. (5 points) 11010101 2 = 213 10 = 325 8 = D5 16 3. (5 points) -37 10 = 1101 1010 (8-bit, one’s complement) = 1101 1011 (8-bit, two’s complement) 4. (5 points) For a word length of 8 bits, if you add -87 10 , and –37 10 using two’s complement arithmetic, do you get an overflow? No. 8-bit two’s complement representation of –87 10 is 1010 1001. When it is added to 1101 1011 (which is the 8-bit two’s complement representation of –37), both carry-in and carry-out bits are equal to 1. So, there cannot be an overflow. 5. (5 points) What are the results of performing arithmetic and logical right-shifts on 10011001 2 ? Give the both answers base-2 form. Arithmetic Right-Shift (ARS): 11001100
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This note was uploaded on 04/25/2010 for the course ECSE ecse-2340 taught by Professor Wozny during the Spring '09 term at Rensselaer Polytechnic Institute.

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InClassActivity01-sol - Last Name Activity #01 (solutions)...

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