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09-Lect-Design Flow Reactor0

# 09-Lect-Design Flow Reactor0 - Outline 1 Design of...

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1 Chemical Reaction Engineering - Musgrave Isothermal CSTR Design Lecture 9 - Page 1 Outline: 1. Design of CSTRs (Fogler 4.3) Next Time: (Fogler 4.4) 1. Design of tubular reactors (Fogler 4.4) Chemical Reaction Engineering - Musgrave Isothermal CSTR Design Lecture 9 - Page 2 CRE Algorithm 1. Choose mole balance 2. Choose rate law 3. Stoichiometry 4. Combine relationships from steps 1, 2, and 3 1. Evaluate expression a. Analytically b. Graphically PFR CSTR Batch 1. Mole Balance 2. Rate Law 3. Stoichiometry Flow Batch 4. Combine 5. Evaluate dV=dV(X) dt=dt(X) V=V(X) t=t(X) Liquid Gas Liquid Gas -r A =f(C A ) -r A =g(C A ) -r A =h(C A )

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2 Chemical Reaction Engineering - Musgrave Isothermal CSTR Design Lecture 9 - Page 3 V = F A 0 X r A Design Equation in terms of X X = r A V F A 0 = r A V C A 0 υ 0 F A0 F A ,F B Does the CSTR have time to do its work? τ = V υ 0 X = r A V F A 0 = r A V C A 0 υ 0 = r A τ C A 0 Chemical Reaction Engineering - Musgrave Isothermal CSTR Design Lecture 9 - Page 4 Upstream volume V V Upstream volume V completely in reactor only after an equal volume of material in reactor removed. V = F A 0 X r A = υ 0 C A 0 X r A 1. CSTR Mole Balance τ = V υ 0 We can use the space-time: To see that: τ = V υ 0 = C A 0 X r A This is equivalent to the CSTR mole balance 2. Rate Law (three examples, 1, 2, and 2’) r A = k A C A r A = k A C A 2 r A = k A C A C B 3. Stoichiometry C A = C A 0 1 X ( ) 4. Combine (for these three rate laws) τ 1 = C A 0 X r A = C A 0 X k A C A = C A 0 X k A C A 0 1 X ( ) = X k A 1 X ( ) τ 2 = C A 0 X r A = C A 0 X k A C A 2 = C A 0 X k A C A 0 2 1 X ( ) 2 = X k A C A 0 1 X ( ) 2 τ 2' = C A 0 X r A = C A 0 X k A
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