09-Lect-Design Flow Reactor0

09-Lect-Design Flow Reactor0 - 1 Chemical Reaction...

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Unformatted text preview: 1 Chemical Reaction Engineering - Musgrave Isothermal CSTR Design Lecture 9 - Page 1 Outline: 1. Design of CSTRs (Fogler 4.3) Next Time: (Fogler 4.4) 1. Design of tubular reactors (Fogler 4.4) Chemical Reaction Engineering - Musgrave Isothermal CSTR Design Lecture 9 - Page 2 CRE Algorithm 1. Choose mole balance 2. Choose rate law 3. Stoichiometry 4. Combine relationships from steps 1, 2, and 3 1. Evaluate expression a. Analytically b. Graphically PFR CSTR Batch 1. Mole Balance 2. Rate Law 3. Stoichiometry Flow Batch 4. Combine 5. Evaluate dV=dV(X) dt=dt(X) V=V(X) t=t(X) Liquid Gas Liquid Gas -r A =f(C A ) -r A =g(C A ) -r A =h(C A ) 2 Chemical Reaction Engineering - Musgrave Isothermal CSTR Design Lecture 9 - Page 3 V = F A X − r A Design Equation in terms of X X = − r A V F A = − r A V C A υ F A0 F A ,F B Does the CSTR have time to do its work? τ = V υ X = − r A V F A = − r A V C A υ = − r A τ C A Chemical Reaction Engineering - Musgrave Isothermal CSTR Design Lecture 9 - Page 4 Upstream volume V V Upstream volume V completely in reactor only after an equal volume of material in reactor removed. V = F A X − r A = υ C A X − r A 1. CSTR Mole Balance τ = V υ We can use the space-time: To see that: τ = V υ = C A X − r A This is equivalent to the CSTR mole balance 2. Rate Law (three examples, 1, 2, and 2’) − r A = k A C A − r A = k A C A 2 − r A = k A C A C B 3. Stoichiometry C A = C A 1 − X ( ) 4. Combine (for these three rate laws) τ 1 = C A X − r A = C A X k A C A = C A X k A C A 1 − X ( ) = X k A 1 − X ( ) τ 2 = C A X...
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This note was uploaded on 04/25/2010 for the course CHEN 4330 taught by Professor Staff during the Spring '08 term at Colorado.

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09-Lect-Design Flow Reactor0 - 1 Chemical Reaction...

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