19-Lect-MultRxns-PFR-CSTR0

19-Lect-MultRxns-PFR-CSTR0 - 1 Chemical Reaction...

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Unformatted text preview: 1 Chemical Reaction Engineering - Musgrave Multiple Rxns in Flow Reactors Lecture 19 - Page 1 Outline: 1. Multiple Reactions in a PFR/PBR (Fogler 6.5) 2. Multiple Reactions in a CSTR (Fogler 6.6) Next Time: (Fogler 7.1) 1. Bioreactions and bioreactors - Active intermediates and non Elementary rates laws (Fogler 7.1) Chemical Reaction Engineering - Musgrave Multiple Rxns in Flow Reactors Lecture 19 - Page 2 PFR CSTR Batch 1. Mole Balance 2. Rate Law -r A =f(C A ) -r A =g(C A ) -r A =h(C A ) 3. Stoichiometry Flow Batch 5. Combine 6. Evaluate dV=dV(X) dt=dt(X) V=V(X) t=t(X) Liquid Gas Liquid Gas dy/dW or dy/dV 4. Pressure Drop PFR CSTR Batch 2. Mole Balance s 3. Net Rates r A 7. Stoichiometry Flow Batch 9. Combine 10. Evaluate dV=dV(X) dt=dt(X) V=V(X) t=t(X) Liquid Gas Liquid Gas dy/dW or dy/dV 8. Pressure Drop 1. Number each reaction r D r C r B Obtaining net rates will require 4 steps Because ODE or equation solver is used, these 2 steps are combined Last 2 steps may be combined if ODEs are coupled 2 Chemical Reaction Engineering - Musgrave Multiple Rxns in Flow Reactors Lecture 19 - Page 3 For a PFR the mole balance is : r i = dF i dV C i = C T F i F T P P T T r NO = k 1 NO C NH 3 C NO 1.5 2 k 2 N 2 C NO 2 r N 2 = 5 6 k 1 NO C NH 3 C NO 1.5 + k 2 N 2 C NO 2 1 2 k 3 O 2 C N 2 C O 2 2 r O 2 = k 2 N 2 C NO 2 k 3 O 2 C NO C O 2 2 So for each species, determine the net rate of formation: 1. 4NH 3 + 6NO 5N 2 + 6H 2 O 2. 2NO N 2 + O 2 3. N 2 + 2O 2 2NO 2 For NH 3 : dF NH 3 dV = r NH 3 = 2 3 r 1 NO = 2 3 k 1 NO C NH 3 C NO 1.5 dF NH 3 dV = 2 3 k 1 NO C TO 2.5 F NH 3 F T F NO F T 1.5 Assume constant T and P For NO: dF NO dV = r NO = k 1 NO C NH 3 C NO 1.5 2 k 2 N 2 C NO 2 dF NO dV = k 1 NO C TO 2.5 F NH 3 F T F NO F T 1.5 2 k 2 N 2 C TO 2 F NO F T 2 Chemical Reaction Engineering - Musgrave Multiple Rxns in Flow Reactors Lecture 19 - Page 4 C i = C T F i F T r NO = k 1 NO C NH 3 C NO 1.5 2 k 2 N 2 C NO 2 r N 2 = 5 6 k 1 NO C NH 3 C NO 1.5 + k 2 N 2 C NO 2 1 2 k 3 O 2 C N 2 C O 2 2 r O 2 = k 2 N 2 C NO 2 k 3 O 2 C NO C O 2 2 1. 4NH 3 + 6NO 5N 2 + 6H 2 O 2. 2NO N 2 + O 2 3. N 2 + 2O 2 2NO 2 For N 2 : dF N 2 dV = r N 2 = 5 6 k 1 NO C NH 3 C NO 1.5 + k 2 N 2 C NO 2 1 2 k 3 O 2 C N 2 C O 2 2 Assume constant T and P For H 2 O: dF N 2 dV = 5 6 k 1 NO C TO 2.5 F NH 3 F T F NO F T 1.5 + k 2 N 2 C TO 2 F NO F T 2 1 2 k 3 O 2 C TO 3 F N 2 F T F O 2 F T 2 dF H 2 O dV = r H 2 O = r 1 NO = k 1 NO C NH 3 C NO 1.5 dF H 2 O dV = k 1 NO C TO 2.5 F NH 3 F T F NO F T 1.5 3 Chemical Reaction Engineering - Musgrave Multiple Rxns in Flow Reactors...
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19-Lect-MultRxns-PFR-CSTR0 - 1 Chemical Reaction...

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