MidtermExam2_Solutions_2009

# MidtermExam2_Solutions_2009 - CHEN 3010 Applied Data...

This preview shows pages 1–3. Sign up to view the full content.

CHEN 3010 Applied Data Analysis Fall 2009 Name:________________________________ Midterm Examination 2 Solutions 1. (10 pts) Minivans represented 29 percent of the 9080 vehicles torn into by bears in Yosemite National Park between 2001 and 2007, even though they made up just 7 percent of the cars that visited Yosemite during that time. Is there evidence that bears preferentially break into minivans over other vehicles? Solution: This is just a simple hypothesis test on a binomial proportion. Since 7% of all cars entering Yosemite are minivans, then the proportion of cars broken into by bears should also be 7% if bears do not preferentially break into minivans over other vehicles. Since 29% of all bear break-ins occur to minivans, it appears that bears preferentially break into minivans, so we want to prove that the proportion is significantly greater than 7%. We can set up the following hypothesis test on the binomial proportion: ܪ : ݌ ൌ 0.07; ܪ :݌൐0.07 We can use the normal approximation to the binomial and compare our test statistic to the standard normal distribution: ݖ ܺെ݊݌ ඥ݊݌ ሺ1 െ ݌ 0.29 · 9080 െ 9080 · 0.07 ඥ9080 · 0.07ሺ1 െ 0.07ሻ ൌ82 .2 We compare this to the critical z-value: ݖ ଴.଴ହ ൌ 1.645 . Since our test statistic far exceeds the critical z-value of 1.645, we accept the alternate hypothesis and claim that bears preferentially break into minivans. 2. (20 pts) The breaking strength of hockey stick shafts made of two different graphite- Kevlar composites yield the following results (in newtons). Assume that breaking strength is normally distributed.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
CHEN 3010 Midterm Exam 1 Fall 2009 Name:________________________________ a. (10 pts) Construct a 95% confidence interval on the ratio 2 2 2 1 / σ to determine if the variances are unequal. Solution: First, we need to determine the sample variances, which are: ݏ ൌ 130.4, ݏ ൌ 319.4 . It appears that ݏ ൏ݏ . We will calculate a 95% confidence interval on 2 2 2 1 / to determine whether or not this interval contains 1. If the interval contains 1, then we conclude that the ratio of the variances could be equal. Our 95% confidence interval is: ݏ ݏ ݂ ଵିఈ ଶ ⁄ ,௡ ିଵ,௡ ିଵ ߪ ߪ ݏ ݏ ݂ ఈଶ ⁄ ,௡ ିଵ,௡ ିଵ 130.4 319.4 · 1 3.85 ߪ ߪ 130.4 319.4 ·4 .30 0.106 ൑ ߪ ߪ ൑1 .75 Conclusion: Since the confidence interval contains 1, we can assume that the variances are equal.
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 04/25/2010 for the course CHEN 3010 at Colorado.

### Page1 / 8

MidtermExam2_Solutions_2009 - CHEN 3010 Applied Data...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online