HW2S - Missing water The horizontal force is calculated...

This preview shows pages 1–5. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
P2.70 Solution: For water, we take ± = 9790 N / m 3 . The hydrostatic force on the valve is : The center of pressure is slightly below the center line by an amount: Taking the moment about the hinge: F = p CG A = h ( ² 4 ) d 2 = (9790 N m 3 ) h ( 4 )(0.2286 m ) 2 = 401.8 h y CP = ± sin ³ I xx F = (9790)sin(30 ± )( ´ / 4)(0.1143) 4 401.8 h = 0.001633 h M hinge = Fl = (401.8 h )(0.15 + 0.00163 h ) = 50 ± h = 0.8187 m
P2.90 For water, we take ± = 9790 N / m 3 . The vertical force on AB is the weight of the missing water above AB-see dashed lines. Calculate this as a rectangle as follow:

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Missing water: The horizontal force is calculated from the vertical projection of panel AB: v = (1.5 m )(0.75)(1.2 m ) + (1 ± ² 4 )(0.75 m ) 2 (1.2 m ) = 1.35 + 0.145 = 1.495 m 3 ³ F V = ´ v = (9790 N / m 3 )(1.495 m 3 ) = 14636.1 N Vertical Force F H = p CG hA projection = (9790 N / m 3 )(1.5 m + 0.375 m )(0.75 m )(1.2 m ) = 16500 N Horizontal force...
View Full Document

{[ snackBarMessage ]}

Page1 / 5

HW2S - Missing water The horizontal force is calculated...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online