Exam I 2005 (Part 2)

Exam I 2005 (Part 2) - ES 223 - Rigid Body Dynamics Exam 11...

Info iconThis preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ES 223 - Rigid Body Dynamics Exam 11 February 23, 2005 NAMEJSECTION S ‘3 lUL‘il M Put your name on the back of the exam also. Closed book and closed notes. Show it]! work and enclose your final answer with a box. Problems will be graded for partial credit only if the: work is neat and an intermediate steps are clearly shown and presented in an easy to follow format. If free body diagrams do not include a coordinate system you will receive very little partial credit. Equations: Uniformly accelerated rectilinear motion: Acceleration due to gavity: d 2 1 g = 32.2 film 3 : 50 + vet +5412 v2 2 v02 + 2a(s — so) Normal/tangential (path) coordinates: 1’ : v5. 2 A M (for circular motion) '2. 2 We» + vet . P v = r6 2 v - - 2 . . an:_—:pfi2=vfl anzv—zrfizzvfl P r a,=1>='s' a,=v:ré a : a"2 + 0,2 Polar coordinates: Quadratic gguation: vzrer+r6iea g=(f—réz)é,+(r§+2fé)ég _ abinz—tiac x: 2a (for circular motion) v, = 0 Power: v3 = r9 PEE— v a, 2 4-6-2 Paw .. em - —_ 00 = r9 'Piuput Work-energy: Tl + UH: : T2 T1 + V3,I + V“I +U"'_,2 = T2 + ng + V‘r1 U=jg-d_r_ T=lmv2 2 1 Um -—§k(x§—x3) (Spnng) V =mgh V‘=—-kx2 Coefficient of restitution: e : (van—(17;), (Vl)n _ (v2)n Selected integmls: j d” =11n(a+bx) a+bx b Isin(a+bx)dx = —%cos(a+bx) Imam + bx)d5c 2 ésinw + bx) 1. (36) The 0.6 kg slider is released from rest at A and slides down the smooth parabolic guide under the influence of its own weight and the spring. The spring constant is 120 Nlm, and the unstretched length of the spring is 200 mm. The guide lies in the vertical plane. (.3) Determine the speed of the slider as it passes point B. The“? 0+0+T73 =- 0.37fBL—a.943+0.)5' 2. (25) The four 5 pound spheres are rigidly attached to the crossbar frame having ' ' ' ' ntM = (0.5: + 0.8) lb-fi, where t is in . The flame is inmaily at rest. (a) Determine the speed of each of the spheres after 4 seconds. eloeity of the flame after 4 seconds. Use (b) Determine the angular v this part of the problem. vector notation for your answer to La) “0‘ + £000 : o + {20.51; +0.2)At -: Lier @ swims) '— Magwyv) db) “UH-u) 3. (5) Stateinwords, Newton’sFirstLaw. a Pennants a‘f Tesi- of continues +0 Nove— umL unrform Velocity {9 Mama 1.: no unbm’ancfll farce 00:"ng on If. 4. (5) The time rate of doing work is called EPOUJ g1: . 5. (35) Two smooth billiard balls, A amrB have equal masses of m = 200 g. A stokes B with a velocity of 15; = 2 m/s as shown. Ball B is originally at rest, and the coefficient of restitution e = 0. 75. Determine the final velocities of the balls just after the collision. Your answers should include the magnitudes of the velocities and arrows that show the directions. Be sure to include the angles that the an'ows make with the horizontal axis. Loaf-Mos 40 = - I332 Ms (an :qsm Ho -' - |~185mI$ ’"U‘at 0 “when ' cmsermiumbi‘ai mameniulm 6'1" 36412»: m “n" dlré'ohm x (n) mm)n+m3(w3jo : meMOM 014307631 M's are :1,“ equal 3:: 44%} cancel Thaw. -I,5'37. -'-‘ (mega +615er ® 6:0.75': @1490 “Offs/)0 _ LUAI)A“MO” I :LI‘Hw‘Pf’ (W); 44.537.) =>WL JO Sub m+o (p: 4.531: 1.149%)" +QJGQnemfla—t3405m Cindi Oral)”:-0.IQ|S (“)5 n 5 Confirm-lam a? mammi-MM 0‘9 €49!“ Paf+'°lc In “ ’5" tithe—chm: mam): me(vn')e 3305;): “1.23599 mm); me (ml 296%” Then 'Un ‘-‘- \imms"? ms 1'= I75 an -‘ 1.7.8; __ z I D 9'9" W (fine) 99“ 8"; ‘-—‘ ‘- ’U’H: L7, m/s 31.5] U8: 036 6"“ ...
View Full Document

This note was uploaded on 04/25/2010 for the course ES 9111 taught by Professor Morrison during the Spring '07 term at Clarkson University .

Page1 / 5

Exam I 2005 (Part 2) - ES 223 - Rigid Body Dynamics Exam 11...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online