This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: l V
rérﬂ ”’“m’ H Uniform
, x G \ _Sle’;de‘l’2R°d ES 223 — Rigid Body Dynamics
\ y I m Exam IV 3 
.71 7131 3 April 18,2007 ' NAME/SECTION Soiu‘lL/U‘YU Closed book and closed notes. Show all work and enclose your ﬁnal answer with a box.
Problems will be graded for partial credit only if the work is neat and all
intermediate steps are clearly shown and presented in an easy to follow format.
Coordinate systems that you use must be clearly drawn. 1, (20) The uniform lookg beam is freely hinged about its n upper end A and is initially at rest in the vertical '44 .5 position with a = 0. Determine the initial angular
acceleration a of the beam and the magnitude FA of g = 0 for the
t the force supported by the pin at A due to the appli Find: 0: and FA A cauan ofa force P = 300 N on the attached cable. 1— inStaFt “m?“
“ _ _ In :éﬂo 0X10 conSIdera’uon!
3m IT ’ ‘_ _ ’IA: 533 Adagio.)—
ﬂat > Lm< \P Ma“ . 300,3“ ENG.1344 _ ~_ _' l“ , _ _ \/ 1 oostus) L3) = 533 e(
“I: 3/3 41/493 (”Cid/$3)
B ZFnlY‘AQ“ :10 2(4):.0; 3 (23) The spool has a mass of. 50 kg and a radius of gyration k0 = 0.280 m. If the 20kg block A is released
from rest, determine the distance the block must fall in
order for the spool to have an angular velocity w = Srad/s. _
Neglect the mass of the rope and friction at 0. _
' 03m I
I; mkz: 50(OZ?)1 "b—a Find: swhenco=5rad/s
1 BIQZ Xiﬁ‘ m1. ' V
T‘4V%'+U:* ;T2‘\\/32 U: VD
T. 2 D _ O 7'“)
V330 v =©1)l5)= Hm
I .—
UI—n. "
.. z. 1 ;%{20)0)+.7£(391)(5)23 59 3"
V31“ *mah: ‘QO)(C\~?‘)(h 3“, 96101) T Theo 4. (2) O = 59— 196.100 Fill 1n the blank with the appropriate word:
The time rate of doing work 15 called P0 W 6 Y‘ 3. (23) The spool has a mass of. 50 kg and a radius of
gyration k0 = 0.280 m. If the 20—kg block A is released
from rest, determine the distance the block must fall in
order for the spool to have an angular velocity
u) = 5 rad/s. Neglect the mass of the rope and friction at 0.
' 0.3m I I}: mg: 3.511 11% m1 "*‘ﬂ" Find: s when a) = 5 rad/s Var spool: For Neck: "Var
2H i, Max M}: m = 0.20%
_T+m%,=C9~°)(0'7—)(°‘) S b QYW® '
:mJoa 4—(120XCL?!) =(go)(o.z)(°2)__ 7_
”13.6% = lam => cl =8.3 :> Q;(o.z)(8:31)=llcb m  57"
v; “(:04 (So'50) Va : o 3 V; = (97.363 4 "‘3 l 1 0+1U'667M5) rm
‘3 =  m 4. (2) Fill in the blank with the appropriate word:
The time rate of doing work is called P 0“) 6" . ...
View
Full Document
 Spring '07
 MORRISON

Click to edit the document details