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Unformatted text preview: 901-948-0681 CEE 498 Construction Project Management Homework #2 1. Net volume of earth fill Dry weight Wet weight Wet weight per unit Volume of pit excavation = (volume of earth fill)*(yd-ft converter) = (187,000 cu yd)*(27 cu ft) = 5049000 cu ft = (volume)*(dry unit weight)*(18.3 % moisture) =(5049000cu ft)*(114 lb/cu ft)*[(100-18.3)/(100)] = 470253762 cu ft = (dry weight)*(1+moisture content) = (470253762 cu ft)(1.165) = 547845632 cu ft = (wet weight) / (wet unit weight) = (547845632 cu ft) / (129 lb/cu ft) = 4246865 lb/cu ft = (wet unit weight) /(in place void ratio) = (4246865 cu ft)/(.620) = 6849782 cu ft = rolling resistance / G% = (100 lb/ton) / (20 lb/ton) = 5% effective grade = adverse grade + equivalent grade = 4% + 5% = 9% = -4% + 5% = 1% 2. Equivalent grade Effective grade Effective grade (return trip) This is because on the return trip, the adverse grade does not effect the hauling units. Finally, the total resistance on the return trip is equal to the rolling resistance les 80 lb/ton = 20 lb/ton. 3. Plant capacity = (production rate tons/hr) / (hr-min converter) Area of materials used Weight of material per unit = (324 tons/hr) / (60 hr/min) = 5.4 tons/min = (Lane area yd-in) = (4 yd)*(2 in) = 8 yd-in = (Amt. material)* (average weight/sq. yd in) / (lbton converter = (8 yd-in)*(112 lb/yd in) / (2000 lb/ton) = 0.4480 ton/ yd in = (plant capacity) / (weight of material) = (5.4 ton/min) / (0.4480 ton/ yd in) = 12.0535 yd-in/min = (min-hr converter) / (cycle time min) = (60 hr/min) / (55 min) = 1.0909 hr/cycle = (truck capacity)*(cycle time hr) = (20 ton)*(1.0909 hr) = 21.8181 ton/truck/hr = (production need) / (truck capacity) = (324 tons/hr) / (21.8181 ton/truck/hr) = 14.85 trucks = 15 trucks Average paver speed Truck cycle time Net truck capacity No. trucks needed ...
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This note was uploaded on 04/25/2010 for the course CEE ID taught by Professor Russeljeffries during the Spring '10 term at Wisconsin.
- Spring '10