Unformatted text preview: i , is zero. The acceleration, represented as a , is downward at 3.71 m/s 2 . The time of 3 seconds is represented as the variable t , in the equation below. v f = v i + a • t v f represents the final velocity . Therefore, the velocity of the rock after 3 seconds is: v f = 0 + 3m/s 2 • 3 = 11.13 m/s We can reasonably assume that the rock will descend faster with each passing second, due to the net force exerted upon it (assuming that on Mars, like here on Earth, “weight is equal to the rock’s mass times the acceleration of gravity,” pg. 15), and as it falls its velocity will continue to increase downward, until it impacts the surface and comes to rest....
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 Spring '09
 STODDARD
 pH, Acceleration, Force, Gravity, Mass, Work, 3 seconds, Professor Stoddard, Professor Stoddard Chapter, 11.13 m/s

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