HW-Sec 1-Prob 3

HW-Sec 1-Prob 3 - i , is zero. The acceleration,...

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Robb Page 03-Feb-2010 Physics 140 Professor Stoddard Chapter 1 – Problem 3 Ques. On Mars, the acceleration of gravity is 3.71 m/s 2 . What would a rock’s velocity be 3 seconds after you dropped it on Mars? For this example we will ignore any effects that may be exerted upon the rock by air resistance, as referenced here on Earth as being negligible, and the same is assumed upon the surface of Mars. We also assume that on Mars the rock’s weight is proportional to the local strength of gravity, “which is measured by a downward vector called acceleration due to gravity” (pg. 15). Since we drop the rock without exerting any additional force, its initial velocity, represented as v
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Unformatted text preview: i , is zero. The acceleration, represented as a , is downward at 3.71 m/s 2 . The time of 3 seconds is represented as the variable t , in the equation below. v f = v i + a t v f represents the final velocity . Therefore, the velocity of the rock after 3 seconds is: v f = 0 + 3m/s 2 3 = 11.13 m/s We can reasonably assume that the rock will descend faster with each passing second, due to the net force exerted upon it (assuming that on Mars, like here on Earth, weight is equal to the rocks mass times the acceleration of gravity, pg. 15), and as it falls its velocity will continue to increase downward, until it impacts the surface and comes to rest....
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