HW-Sec 1-Prob 4 - 2 If we plug in the data as provided from...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Robb Page 10-Feb-2010 Physics 140 Professor Stoddard Chapter 1 – Problem 4 Ques. How far would a rock fall in 3 seconds if you dropped it on Mars? (See Problem 3). We will overlook any effect of air resistance since it is deemed to be negligible in this example. To recap from Problem 3, for an object that falls from rest, the initial velocity is zero, and the acceleration is downward at 3.71m/s 2 , and the primary interaction is gravity between the surface of Mars and the rock. The question asks us to observe the distance the rock will fall in 3sec, so we need to calculate its position relative to time. “To calculate position, we must know these things: the initial position, initial velocity, acceleration, and time” (pg. 19). Written out, it looks as such... Present position = initial position + initial velocity
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2 If we plug in the data as provided from Problem 3, our equation is as follows: = 0 + 0m/s • 0s + (½) • (-3.71m/s 2 ) • 3s ≈-16.7m To ensure consistency for measuring along the vertical axis we will assume that the initial position is zero, regardless of the person’s height, since this tends to vary. So even though a 6ft man may drop a rock onto the surface of Mars, whereby the rock will fall a distance of 1.8288m striking the ground in just under 1 second, we can use the above calculation to project where the rock’s given position is relevant to the amount of time in free fall (with no other forces upon it) …as opposed, to say, standing on a precipice and attempting to measure the distance manually....
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern