HW-Sec 1-Prob 4 - 2 If we plug in the data as provided from...

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Robb Page 10-Feb-2010 Physics 140 Professor Stoddard Chapter 1 – Problem 4 Ques. How far would a rock fall in 3 seconds if you dropped it on Mars? (See Problem 3). We will overlook any effect of air resistance since it is deemed to be negligible in this example. To recap from Problem 3, for an object that falls from rest, the initial velocity is zero, and the acceleration is downward at 3.71m/s 2 , and the primary interaction is gravity between the surface of Mars and the rock. The question asks us to observe the distance the rock will fall in 3sec, so we need to calculate its position relative to time. “To calculate position, we must know these things: the initial position, initial velocity, acceleration, and time” (pg. 19). Written out, it looks as such. .. Present position = initial position + initial velocity • time + ½ • acceleration • (time)
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Unformatted text preview: 2 If we plug in the data as provided from Problem 3, our equation is as follows: = 0 + 0m/s • 0s + (½) • (-3.71m/s 2 ) • 3s ≈-16.7m To ensure consistency for measuring along the vertical axis we will assume that the initial position is zero, regardless of the person’s height, since this tends to vary. So even though a 6ft man may drop a rock onto the surface of Mars, whereby the rock will fall a distance of 1.8288m striking the ground in just under 1 second, we can use the above calculation to project where the rock’s given position is relevant to the amount of time in free fall (with no other forces upon it) …as opposed, to say, standing on a precipice and attempting to measure the distance manually....
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This note was uploaded on 04/25/2010 for the course PHYS 140 taught by Professor Stoddard during the Spring '09 term at University of Missouri-Kansas City .

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HW-Sec 1-Prob 4 - 2 If we plug in the data as provided from...

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