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HW-Sec 10-Prob 23

# HW-Sec 10-Prob 23 - V = 15 A ∙ 0.04 Ohms = 0.6 volts The...

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Robb Page 12-Apr-2010 Physics 140 Professor Stoddard Chapter 10 – Problem 23 Ques. Each of the two wires in a particular 16-gauge extension cord has an electric resistance of 0.04 Ohms. You’re using this extension cord to operate a toaster oven, so a current of 15 Amps is flowing thru it. What is the voltage drop across each wire in this extension cord? This is solved using Ohm’s law for determining the relationship between voltage drop and current, and can be worded as such: voltage drop = current electrical resistance …or in symbols: V = I R Therefore, we calculate the voltage drop as such:

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Unformatted text preview: V = 15 A ∙ 0.04 Ohms = 0.6 volts The product of the current and the electrical resistance results in a voltage drop of 0.6 volts across each wire. Of course, in my drawing the length of the extension cord could easily be assumed to be 25 feet. Since the problem didn’t mention the length of the cord, I took liberties with my 15 amps (current) 16-gauge (extension cord) 0.04 Ohms (electrical resistance) 0.6 volts (voltage drop) diagram for artistic effect, but I wonder: if the greater the length of the wires would the voltage drop be greater, due to increased resistance? I think, yes....
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HW-Sec 10-Prob 23 - V = 15 A ∙ 0.04 Ohms = 0.6 volts The...

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