QSol1 - / s , v A y = √ 2 sin 45 ◦ = 1 m / s . (b) Find...

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MAE2082: Quiz 1 , . January 26, 2010 Last Name First Name Student ID Problem 1 A rocket is fired at a point A of a slope, and it hits the slope at another point B . The angle between the initial velocity vector ~v A and the horizontal direction is 45 , and the angle between the horizontal direction and the slope is also 45 . The initial speed of the rocket is v A = 2 m / s . Assume that there is a gravitational acceleration g = 9 . 81 m / s 2 . We want to find the flight time t AB . - 6 ± ± ± ± ±² ? . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . r r x horizontal direction y A B 45 45 v A = 2m / s g slope @ @ @ @ @ @ @ @ @ @ @ @ @ @ @ (a) What are x A ,y A ,v A x ,v A y . x A = 0 , y A = 0 , v A x = 2 cos 45 = 1 m
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Unformatted text preview: / s , v A y = √ 2 sin 45 ◦ = 1 m / s . (b) Find the expression of x B in terms of t AB . x B = x A + V A x t AB = t AB m ( t AB should be in seconds) . (c) Find the expressison of y B in terms of t AB . y B = y A + V A y t AB-1 2 gt 2 AB = t AB-4 . 905 t 2 AB m ( t AB should be in seconds) . (d) Using the fact that x B =-y B , compute t AB . t AB =-t AB + 4 . 905 t 2 AB , t AB (2-4 . 905 t AB ) = 0 , t AB = 0 or t AB = 2 4 . 905 = 0 . 408 , t AB = 0 . 408 sec ....
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This note was uploaded on 04/25/2010 for the course MAE 2082 taught by Professor Yang during the Spring '08 term at FIT.

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