Chem 153A, Winter 2009
Practice Final 2 Answer Key
a, c, d, g, h
The A→B reaction is highly spontaneous and
would lead to a buildup of B in the cell.
buildup would be enough to make B→C
The phosphoryl group of ATP is a
better electrophile than C6 of glucose.
a, b, c, d
I, M, N, O, Q, R, V
E, M, N, Q
C, E, A, B, D
Lipoic acid is covalently bound to one or
more lysines in E
, so if there are no lysines,
there is no lipoic acid, and no catalytic
PDH is not used in anaerobic metabolism, so
growth would be unaffected.
PDH is necessary for aerobic metabolism, so
growth would be severely reduced (to only
what you’d get under anaerobic conditions).
You mutated α-ketoglutarate DH E
of PDH E
, which would likewise eliminate
Before round 1: C3 & 4 leave (pyruvate →
TCA round 1: no additional carbons released
1/3 of C’s
tot. = 1/3 + 1/3 = 2/3
TCA round 3: ½ of C1 & 6 leave (same steps as
½ of 1/3 = 1/6 of C’s
tot.= 2/3+1/6 = 5/6
The pyruvate carboxylase reaction uses ATP, so
the cell shouldn’t run the reaction unless
oxaloacetate is absolutely needed.
presence of acetyl-CoA indicates that the energy