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hwk_6_solutions

hwk_6_solutions - 2 CE ZHSO~OI EMBLEM No:53 f A VERTICfiL...

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Unformatted text preview: 2 CE ZHSO~OI EMBLEM No; :53 f . A VERTICfiL FORCE OF 200E115. QEQWEED'TD REMOVE w! 1 THE NE1L.-DETEEZMH\1E. . . g 1 COTE-1E MDMENT Mom? 13. 0F TEE EEEEE JET C - La; 1' E)TH1. MEGMWDE \oF P THEFT GEE/HES THE SAME t 1 ' (Aw/rm :3 M1}MEN'§‘IF 0(7— CJTHE SMHELEsT FoEEE D THE? CQEA-EE? THE SEME MOMENT i 01) “200% - Mg "—- i'xflf) i ax».- ‘300 E (0.11:) FEM“) h- (11:)? } $760,510 ' E a 5?}?- E '/‘ 1 .1 M31613)?! . I gEoo / A ”I? 2 P. : ELLE E 17"15 TEE: mmumm OF. P {Vi £733 Mm M! m n PROBLEM NO- 3, H THE MOMENT ”fing 0 Mug”? 12:5 61W»: M AND Ag 0W) = +51 (MOUNT/15$ ABOLAT D _ 0] (t2 0 cl «"1 W .3 0/, 2% 00 3M{} - £3124. —' Simblo .O‘Z .- Mafia Orgqa'LGSii/‘d 7" OZSivflQ ' d?" 59h" 0.: >503? 0.?CHQ2 GEL”: MD : QQO‘: [9/4“ 23:332. mam. 7 _ 29:90” +4 an d) tho I Z 2%00 aim \213'3 9:5 E, awrtzagurgs N0 MOMENT . HAS A MAXTMMM of quofi DETERMINE THE _ . . MIN1MMM VALVE a? d _ __ _—‘_L ' > ; lOfl‘V 3’? 12% Co. Af’DDL/‘LT A- 2 373 m 1-2 \W [2551mmfl‘fi +6»); .. ”f 2 31M 2 ,, g; j!" " '2‘. a 3 r ‘ +0134 8 Fr fi- I . i W._ . , ._ ,.-_ u ‘ .. a; ...-.. W. W m . . __,_..__. i , . i ‘ . 5cm“. , ‘ . mammmww E Z ‘25 Chg, DETEQI‘A 5.7315 THQ Mgmggg“ N) a}? I? % ...
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