Chap-08 IP - Chapter8 Internet Protocol Objectives Upon completion you will be able to Understand the format and fields of a datagram Understand

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TCP/IP Protocol Suite 1 Chapter   8 Chapter   8 Upon completion you will be able to: Internet Protocol Internet Protocol Understand the format and fields of a datagram Understand the need for fragmentation and the fields involved Understand the options available in an IP datagram Be able to perform a checksum calculation Understand the components and interactions of an IP package Objectives
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TCP/IP Protocol Suite 2 Figure 8.1 Position of IP in TCP/IP protocol suite
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TCP/IP Protocol Suite 3 8.1 DATAGRAM A packet in the IP layer is called a datagram, a variable-length packet A packet in the IP layer is called a datagram, a variable-length packet consisting of two parts: header and data. The header is 20 to 60 bytes in consisting of two parts: header and data. The header is 20 to 60 bytes in length and contains information essential to routing and delivery. length and contains information essential to routing and delivery.
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TCP/IP Protocol Suite 4 Figure 8.2 IP datagram
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TCP/IP Protocol Suite 5 Figure 8.3 Service type or differentiated services
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TCP/IP Protocol Suite 6 The precedence subfield was designed, but never used in version 4. Note: Note:
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TCP/IP Protocol Suite 7 Table 8.1 Table 8.1 Types of service Types of service
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TCP/IP Protocol Suite 8 Table 8.2 Table 8.2 Default types of service Default types of service
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TCP/IP Protocol Suite 9 Table 8.3 Table 8.3 Values for codepoints Values for codepoints
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TCP/IP Protocol Suite 10 The total length field defines the total length of the datagram including the header. Note: Note:
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TCP/IP Protocol Suite 11 Figure 8.4 Encapsulation of a small datagram in an Ethernet frame
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TCP/IP Protocol Suite 12 Figure 8.5 Multiplexing
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TCP/IP Protocol Suite 13 Table 8.4 Table 8.4 Protocols Protocols
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TCP/IP Protocol Suite 14 An IP packet has arrived with the first 8 bits as shown: Example 1 01000010 The receiver discards the packet. Why? Solution There is an error in this packet. The 4 left-most bits (0100) show the version, which is correct. The next 4 bits (0010) show the header length; which means (2 × 4 = 8), which is wrong. The minimum number of bytes in the header must be 20. The packet has been corrupted in transmission.
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TCP/IP Protocol Suite 15 In an IP packet, the value of HLEN is 1000 in binary. How many bytes of options are being carried by this packet? Example 2 Solution The HLEN value is 8, which means the total number of bytes in the header is 8 × 4 or 32 bytes. The first 20 bytes are the base header, the next 12 bytes are the options.
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TCP/IP Protocol Suite 16 In an IP packet, the value of HLEN is 5 16 and the value of the total length field is 0028 16 . How many bytes of data are being carried by this packet? Example
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This note was uploaded on 04/26/2010 for the course CSE CS501 taught by Professor Dmathur during the Winter '10 term at National Institute of Technology, Calicut.

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Chap-08 IP - Chapter8 Internet Protocol Objectives Upon completion you will be able to Understand the format and fields of a datagram Understand

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