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# ch67 - V1avg2(2g p1(g z1=V2avg2(2g p2(g z2 hlT Bernoulli's...

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Allows calculations of capacity of an oil pipe line, what diameter water main to install or pressure drop in an air duct, …… α V 1avg 2 / (2g) + p 1 /( ρ g) + z 1 = α V 2avg 2 / (2g) + p 2 /( ρ g) + z 2 + h lT Bernoulli’s Equation one of the most important and useful equations in fluid mechanics Fox et al. h lT has units of enery per unit weight which equals length

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+ α V 1avg 2 / (2g) + p 1 /( ρ g) + z 1 = α V 2avg 2 / (2g) + p 2 /( ρ g) + z 2 + h lT V = Q/Area Does not include losses due to entrance, pipe fittings, expansion, exit,…
α V 1avg 2 /2 + p 1 / ρ + gz 1 - α V 2avg 2 /2 - p 2 / ρ - gz 2 = Σ f [L/D][V 2 /2] + Σ f [L e /D][V 2 /2] + Σ K[V 2 /2] p 1 /( ρ g) - p 2 /( ρ g) = f [L/D][V avg 2 /(2 g)] + h lm pipe minor losses: entrance, exit, valves,… Only losses in fully developed laminar and turbulent pipe flow ; does not include entrance, exit, expansions, contraction, elbow, bends, valves, other pipe fittings .

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Pipe Flow Examples ~ Solving for pressure drop in horizontal pipe
Air flows through 4.0 mm diameter drawn tubing ( ε = 0.0015 mm) at V = 50 m/s. Calculate Δ p per 0.1 m if flow is laminar ?

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ch67 - V1avg2(2g p1(g z1=V2avg2(2g p2(g z2 hlT Bernoulli's...

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