hw4_sol - (10) Problem 9.79 from White Remember that there...

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( 10 ) Problem 9.79 from White Remember that there is a subsonic and supersonic solution to Eq 9.45 (look at figure 9.7) so you needed to reason that you were interested in the supersonic solution (because had to be supersonic before shock). --------------------------- ( 11 ) Problem 9.63 from White In words. Started at the very left where po = pambient. Because isentropic to shock, pambient = po1 just before shock. Can get M 1 from Eq. 9.45 or Table B.1 since know A1 and A*. Can get po2 across shock from B.2 (or 9.58) which equals po3 since isentropic. To get p3 need M3 and again Eq 9.45 or B.1. Get M3 from since know A3 and can find A*3 = A*2 from Table B.1 or eq. 9.59. -------------------------- ( 12 ) Problem 9.72 from White --------------------------------------------------- ( 13 )Given : Air in a large tank on a space shuttle leaves through a converging section. T 1 = 0 o C A 2 = 0.001 m 2 , m rate = 2 kg/s, P 2 = 0 Find : a) T 2 b) V 2 c) P 2 d) P 1 Assumptions : (1) Steady flow (2) Isentropic flow (3) V 1 = 0 (4) Air is an ideal gas Equations : Speed of sound: , , Ideal gasses: , c = V/M Isentropic flow:
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This note was uploaded on 04/26/2010 for the course MAE 101B 101B taught by Professor Rohr during the Summer '09 term at UCSD.

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hw4_sol - (10) Problem 9.79 from White Remember that there...

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