Problem 2-3 - MACHINE DESIGN - An 2-3-1 PROBLEM 2-3...

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MACHINE DESIGN - An 2-3-1 PROBLEM 2-3 Statement: Which of the steel alloys shown in Figure 2-19 would you choose to obtain (a) Maximum strength (b) Maximum modulus of resilience (c) Maximum modulus of toughness (d) Maximum stiffness Units: ksi 10 3 psi . MPa 10 6 Pa . GPa 10 9 Pa . MN 10 6 newton . Given: Young's modulus for steel E 207 GPa . Solution: See Figure 2-19 and Mathcad file P0203. 1. Determine from the graph values for yield strength, ultimate strength and strain at fracture for each material. Steel Yield Strength Ultimate Strength Fracture Strain AISI 1020: Sy 1020 300 MPa . Sut 1020 400 MPa . ε f 1020 0.365 AISI 1095: Sy 1095 550 MPa . Sut 1095 1050 MPa . f 1095 0.11 AISI 4142: Sy 4142 1600 MPa . Sut 4142 2430 MPa . f 4142 0.06 Note: The 0.2% offset method was used to define a yield strength for the AISI 1095 and the 4142 steels. 2. From the values of S ut above it is clear that the AISI 4142 has maximum strength. 3.
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Problem 2-3 - MACHINE DESIGN - An 2-3-1 PROBLEM 2-3...

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