Problem 2-12

# Problem 2-12 - See Mathcad file P0212 1 Determine the...

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MACHINE DESIGN - An 2-12-1 PROBLEM 2-12 Statement: A steel has a yield strength of 60 kpsi (414 MPa), an ultimate tensile strength of 100 kpsi (689 MPa), and an elongation at fracture of 15%. What is its approximate modulus of toughness? What is the approximate modulus of resilience? Units: ksi 10 3 psi . MN 10 6 newton . MPa 10 6 Pa . kip 10 3 lbf . kN 10 3 newton . Given: S y 60 ksi . S ut 100 ksi . ε f 0.15 S y 414 MPa = S ut 689 MPa = Solution:
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Unformatted text preview: See Mathcad file P0212. 1. Determine the modulus of toughness using Equation (2.8). U T S y S ut 2 f . U T 12000 lbf in . in 3 = U T 82.7 MN m . m 3 = 2. Determine the modulus of resilience using Equation (2.7) and Young's modulus for steel: E 30 10 6 . psi . U R 1 2 S y 2 E . U R 60 lbf in . in 3 = U R 414 kN m . m 3 = P 0212.mcd...
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## This note was uploaded on 04/26/2010 for the course MAE 3242 taught by Professor N/a during the Spring '10 term at University of Texas-Tyler.

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