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Problem 2-22

# Problem 2-22 - 4 N m 3 = Mat 4"Ti-75A Titanium"...

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MACHINE DESIGN - An 15-1-1 PROBLEM 2-22 _____ Statement: Refer to the tables of material data in Appendix C and determine the strength-to-weight ratios of the following material alloys based on their ultimate tensile strengths: heat-treated 2024 aluminum, SAE 1040 cold-rolled steel, unfilled acetal plastic, Ti-75A titanium, type 302 cold-rolled stainless steel. Units: MPa 10 6 Pa . Given: Material Tensile Strength Specific Weight Mat 1 "2024 Aluminum, HT" Sut 1 441 MPa . γ 1 0.10 lbf . in 3 . 1 2.71 10 4 . Nm 3 . = Mat 2 "1040 CR Steel" Sut 2 586 MPa . 2 0.28 lbf . in 3 . 2 7.60 10 4 . Nm 3 . = Mat 3 "Acetal, unfilled" Sut 3 60.7 MPa . 3 0.051 lbf . in 3 . 3 1.38 10
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Unformatted text preview: 4 . N m 3 . = Mat 4 "Ti-75A Titanium" Sut 4 586 MPa . 4 0.16 lbf . in 3 . 4 4.34 10 4 . N m 3 . = Mat 5 "Type 302 CR SS" Sut 5 1310 MPa . 5 0.28 lbf . in 3 . 5 7.60 10 4 . N m 3 . = i 1 2 , 5 .. Solution: See Mathcad file P0222. 1. Calculate the strength-to-weight ratio for each material as described in Section 2.1. SWR i Sut i i SWR i 10 4 m . 1.625 0.771 0.438 1.349 1.724 = Mat i "2024 Aluminum, HT" "1040 CR Steel" "Acetal, unfilled" "Ti-75A Titanium" "Type 302 CR SS" = P 0222.mcd...
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