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Unformatted text preview: CE- 215 Spring 2010 Exam 1, 50 minutes, 1 page of notes and calculator allowed NAME:______________________________ Student ID (Last four digits): ________ =E=G=N x( )dxEA x( )LT=T( )T=TL=T( )Lmax=rddx=rmax=r=rL==rmaxmax=Gr=G=rmaxIp=r42=d432=ii=1n=TiLiGiIpiii=1n=dL=T dxGIpx( )L=dL=Tx( )dxGIpx( )LPROBLEM 1(30pts) A steel rod, connected to a steel plate of diameter 30 mm and thickness 11 mm as shown, is subjected to load P and supported by an aluminum plate 12 mm thick into which a 10 mm diameter hole has been drilled. The allowable shear stress in the aluminum is 65 MPa and in the steel 170 MPa. Further, the bearing stress between the steel and the aluminum is not to exceed 250 MPa. Determine the largest load P that can be applied. Ignore all weights. Solution The area sheared in the aluminum is (30 mm)(12 mm) = 1,130.4 mm2= 1,130.4 10-6m2....
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