This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: The center of the circle is at (15000+8000)/2 = 11500 psi. Point A is at (15000,-2000). These yield the following circle Stress Transformation: 13 A simple tension element is made from two shorter pieces of material with the glue joint at 15° from the loading axis. Using Mohr’s circle, find the shear and normal stresses at the Solution Stress element. The center of the circle is at (250+0)/2 = 125 psi. Point A is at (250,0). These yield the following circle Rotate initial stress element. θ = -75° sin(2 θ ) = -0.5 cos(2 θ ) = -0.866...
View Full Document
This note was uploaded on 04/28/2010 for the course CE 215 taught by Professor Frantziskonis during the Spring '08 term at Arizona.
- Spring '08
- Shear Stress