# Hw9 - The center of the circle is at(15000 8000/2 = 11500...

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Stress Transformation: 10 For the stress element in Problem 3(b), find the principal stresses and the maximum shear stress. Solution Stress Transformation: 11 For the stress element in Problem 3(a), find the principal stresses and the maximum shear stress using Mohr’s circle. Solution The center of the circle is at (12000-4000)/2 = 4000 psi. Point A is at (12000,1000). These yield the following circle

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Stress Transformation: 12 For the stress element in Problem 3(b), find the principal stresses and the maximum shear stress using Mohr’s circle. Solution
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Unformatted text preview: The center of the circle is at (15000+8000)/2 = 11500 psi. Point A is at (15000,-2000). These yield the following circle Stress Transformation: 13 A simple tension element is made from two shorter pieces of material with the glue joint at 15° from the loading axis. Using Mohr’s circle, find the shear and normal stresses at the Solution Stress element. The center of the circle is at (250+0)/2 = 125 psi. Point A is at (250,0). These yield the following circle Rotate initial stress element. θ = -75° sin(2 θ ) = -0.5 cos(2 θ ) = -0.866...
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## This note was uploaded on 04/28/2010 for the course CE 215 taught by Professor Frantziskonis during the Spring '08 term at Arizona.

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Hw9 - The center of the circle is at(15000 8000/2 = 11500...

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