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Unformatted text preview: index for energy-limited failure under fracture at minimum mass. Hint: Recall that toughness is the integral of the stress-strain curve (energy), and find an index that will maximize fracture toughness. M2 > 0.25 required. We are given 4 formulas. , , , For part a), this is how I solved it. , divide both sides by E., we know, , so substituting gives me, all in all. .. so. .. to maximize the fracture toughness, under displacement-limited design. b) so i get. .....
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- Fall '09