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Unformatted text preview: a Method of Lagrange multipliers Suppose we wish to nd the maximum and minimum values of a function f ( x , y ) along a curve specied by g ( x , y ) = k . We must nd where f is parallel to g . This occurs when f = g . The solution to the optimization problem is the solution to the following set of equations f = g g ( x , y ) = k Lecture 10 1 2 : Maximum and Minimum Values Subject to Contr a Class exercise Find the maximum and minimum values of the function f ( x , y ) = 4 x + 6 y subject to the constraint x 2 + y 2 = 13. Lecture 10 1 2 : Maximum and Minimum Values Subject to Contr a Class exercise Find the maximum and minimum values of the function f ( x , y ) = 4 x + 6 y subject to the constraint x 2 + y 2 = 13. Answer: f (2 , 3) = 26 is the maximum. f (2 , 3) =26 is the minimum. Lecture 10 1 2 : Maximum and Minimum Values Subject to Contr a...
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This note was uploaded on 04/29/2010 for the course MATH 200 taught by Professor Unknown during the Spring '03 term at The University of British Columbia.
 Spring '03
 Unknown
 Multivariable Calculus

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