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Unformatted text preview: Difference scores = 3, 3, 2, 7, 8 Mean of D = 2.6; Estimated population variance = SS / df = 25.3 Variance of the distribution of means = 25.3 / 5 = 5.06 Standard deviation of the distribution of means = √ 5.06 = 2.25 Standard error = 2.25 / √ 5 = 1.00 t = (M  μ ) / Standard error t = 2.6 – 0) / 1.00 =  2.6 Decision: Reject the null hypothesis. The psychologist’s program does significantly reduce test anxiety. #6. t test for dependent means (Matched t test) t needed (df = 4), alpha = .05, 1tailed = 2.132 Difference scores = .07, .18, .14, .18, .13 M = .088; Estimated population variance = SS / df = .017 Variance of the distribution of means = .017 / 5 = .003 Standard deviation of the distribution of means = √ .003 = .055 Standard error = .025 t = (M  μ ) / Standard error t = (.088 – 0) / .025 = 3.52 Decision: Reject the null hypothesis. There is a difference in time for the kinds of words....
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 Winter '10
 AfroditiPanagopoulos
 Statistics, Normal Distribution, Standard Deviation, Variance, population variance

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