Unformatted text preview: 8 instr) x (3 cycles / instr) x (10-9 seconds / cycle) = 1.5 seconds 2. (4 points) Suppose we enhance a computer to make all floating-point instructions run five times faster. If the execution time of some benchmark before the floating-point enhancement is 10 seconds, what will the execution time of the same benchmark after the floating-point enhancement be, if half of the 10 seconds is spent executing floating-point instructions? Amdahl’s law: Time taken after enhancement = (5/5) + 5 = 6 seconds...
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- Spring '08
- Central processing unit, CPU time, Average CPI