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M325K_HW02_Soln

# M325K_HW02_Soln - M325K HW 02 Solutions to Graded...

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M325K HW 02 - Solutions to Graded Questions ( Out of 25 points) Section 1.3 23. (4pts) Its form: q p q p r q ~ premises conclusion 28 . (2pts) Its form is: q p Invalid, a converse error. q p 38. (5pts) c) Answer: There is only one knave and only one knight. There are 4 cases to consider, namely a) Both are knights c) E is a knight and F is a knave. b) Both are knaves d) E is a knave and F is s knight. Observe that (a) is not possible, because then both would also be telling the truth and both would also be knaves. Similarly, (b) is not possible because in this case both would be telling the truth which would make them knights, a contradiction. Hence there is only one knight and only one knave. Note that in case c and d, both E and F would have spoken as reported, without a contradiction. It is OK if you combine c and d and consider it as “if one is a knight and the other is a knave”. But

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M325K_HW02_Soln - M325K HW 02 Solutions to Graded...

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