Quest HW 6-solutions

Quest HW 6-solutions - syed(sms3768 – Quest HW 6 –...

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Unformatted text preview: syed (sms3768) – Quest HW 6 – seckin – (56425) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Find y ′ when xy + 3 x + 4 x 2 = 2 . 1. y ′ =- ( y + 3 + 8 x ) 2. y ′ = 3 + 4 x- y x 3. y ′ = y + 3 + 8 x x 4. y ′ = y + 3 + 4 x x 5. y ′ =- y + 3 + 8 x x correct 6. y ′ =- y + 3 + 4 x x Explanation: Differentiating implicitly with respect to x we see that d dx ( xy + 3 x + 4 x 2 ) = d dx (2) . Thus ( xy ′ + y ) + 3 + 8 x = 0 , and so xy ′ =- y- 3- 8 x . Consequently, y ′ =- y + 3 + 8 x x . 002 10.0 points Find dy dx when 1 √ x + 3 √ y = 6 . 1. dy dx =- 1 3 parenleftBig y x parenrightBig 3 / 2 correct 2. dy dx = 1 3 parenleftBig y x parenrightBig 3 / 2 3. dy dx = 3 parenleftBig x y parenrightBig 3 / 2 4. dy dx = 3( xy ) 1 / 2 5. dy dx =- 3 parenleftBig x y parenrightBig 3 / 2 6. dy dx = 1 3 ( xy ) 1 / 2 Explanation: Differentiating implicitly with respect to x , we see that- 1 2 parenleftBig 1 x √ x + 3 y √ y dy dx parenrightBig = 0 . Consequently, dy dx =- 1 3 parenleftBig y x parenrightBig 3 / 2 . 003 10.0 points Find dy dx when 3 √ x + 2 √ y = 5 ....
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This note was uploaded on 04/29/2010 for the course MATH 408K taught by Professor Seckin during the Spring '10 term at University of Texas-Tyler.

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Quest HW 6-solutions - syed(sms3768 – Quest HW 6 –...

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