PROJECTILE MOTION tutorial

PROJECTILE MOTION tutorial - PROJECTILE MOTION EVERYTHING...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
PROJECTILE MOTION, EVERYTHING YOU NEED TO KNOW Projectile motion is a special case of two- dimensional constant acceleration. It is special because the horizontal or x-component of acceleration can be approximated as zero. The vertical or y-component of acceleration is approximated as g . The initial x-position is defined as zero (x 0 = 0). The direction or the trajectory angle θ is defined with respect to the horizontal. θ is positive if the object is rising, it is zero if it is moving horizontally, and it is negative if it is falling. For θ 0 > 0, we define the positive y-axis as up: y and a y = g = -g If 0 θ 0, then y and a y = g = + g. v x 0 = v 0 cos 0 θ and v y 0 = v 0 sin 0 θ where v 0 is the initial speed and 0 θ is the initial projection angle. (1) x = v x 0 t Horizontal position as a function of time (2) y = y 0 + v y 0 t + 1/2 g t 2 Vertical position as a function of time (3) v y = v y 0 + g t Vertical velocity as a function of time (4) v y 2 = v y 0 2 + 2 y g Scalar or time independent equation (5) y = 1/2 ( v y 0 + v y
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern