HW2-1 - Now we just need to find the surface area 2 4 r A...

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Spherical Shell Insulator Given: Find: cm a 4 ? y E cm b 6 C Q 9 ) 5 , 0 ( cm P Solutions a.) To find y E we can use the following formula: According to Gauss’ Law 0 enc Q A d E Since the E field is pointing down we get the following formula: 0 enc Q EdA 0 enc Q EA 0 A Q E enc Now we just need to find the surface area of the sphere (r=5cm) and the enclosed Q First let’s find the enc Q We know that V Q density The volume is:   3 3 3 3 3 4 3 4 3 4 a b a b   3 3 3 4 a b Q V Q
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      3 3 3 3 3 3 3 3 3 3 3 3 3 4 3 4 3 4 3 4 3 4 a b a r Q a b Q a r a b Q a r V Q enc enc
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Unformatted text preview: Now we just need to find the surface area 2 4 r A Finally put everything together: 3 3 2 3 3 2 3 3 3 3 4 4 a b r a r Q r a b a r Q A Q E enc note: r ( must be positive ) = y position 3 3 2 3 3 4 a b r a r Q E...
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HW2-1 - Now we just need to find the surface area 2 4 r A...

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