# HW2-1 - Now we just need to find the surface area 2 4 r A...

This preview shows pages 1–2. Sign up to view the full content.

Spherical Shell Insulator Given: Find: cm a 4 ? y E cm b 6 C Q 9 ) 5 , 0 ( cm P Solutions a.) To find y E we can use the following formula: According to Gauss’ Law 0 enc Q A d E Since the E field is pointing down we get the following formula: 0 enc Q EdA 0 enc Q EA 0 A Q E enc Now we just need to find the surface area of the sphere (r=5cm) and the enclosed Q First let’s find the enc Q We know that V Q density The volume is:   3 3 3 3 3 4 3 4 3 4 a b a b   3 3 3 4 a b Q V Q

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
      3 3 3 3 3 3 3 3 3 3 3 3 3 4 3 4 3 4 3 4 3 4 a b a r Q a b Q a r a b Q a r V Q enc enc
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Now we just need to find the surface area 2 4 r A Finally put everything together: 3 3 2 3 3 2 3 3 3 3 4 4 a b r a r Q r a b a r Q A Q E enc note: r ( must be positive ) = y position 3 3 2 3 3 4 a b r a r Q E...
View Full Document

## This note was uploaded on 05/01/2010 for the course PHYS 212 taught by Professor Selen during the Fall '08 term at University of Illinois at Urbana–Champaign.

### Page1 / 2

HW2-1 - Now we just need to find the surface area 2 4 r A...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online