Week 6 - There is no value of F that will allow force...

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Odd problem answers from the solutions manual HW problems 4.59 Systems (a) and (c) are equivalent, and systems (b) and (d) are equivalent 4.65 F = ( - 1490 i – 102 j) lb; x = 50.1 in. 4.69 F = (0 i + 0 j – 2490 k) lb; M = (- 13900 i + 0 j + 0 k) in.- lb Additional problems 4.61 F = 200 N and M = 2000 n-m for systems (a) and (b) to be equivalent F = -100 N and P = 100 N for force systems (a) and (c) to be equivalent
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Unformatted text preview: There is no value of F that will allow force systems (a) and (d) to be equivalent 4.63 (a) F = (0 i 2900 j + 0 k) N; M = (-2500 i + 0 j + 0 k) N-m (b) F = (0 i 2900 j + 0 k) N; x = 0, z = - 0.862 m Challenge problems 4.77 F = 10 k N, M = 6 k N-m; the line of action of the wrench intersects the xy plane at x = 0.6 m, y = 0....
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This note was uploaded on 05/01/2010 for the course EMCH 212 taught by Professor Cusumano during the Spring '08 term at Pennsylvania State University, University Park.

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