circuits_Test3Solution

# circuits_Test3Solution - Solution of ECE 300 Test 3 F09 1...

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Unformatted text preview: Solution of ECE 300 Test 3 F09 1. In the circuit below R 1 = 5 Ω , R 2 = 15 Ω , R 3 = 20 Ω , R 4 = 10 Ω , V s = 20V and I s = 1A . (a) The current I x can be expressed in terms of the node voltages v 1 , v 2 and v 3 . Fill in each blank in the equation with a single number. I x = _________ ( ) v 1 + __________ ( ) v 2 + __________ ( ) v 3 I x = 1 / 5 ( ) v 1 + 1 / 20 ( ) v 2 + ( ) v 3 OR v 3 − v 2 10 = I x / 5 ⇒ I x = ( ) v 1 − 1 / 2 ( ) v 2 + 1 / 2 ( ) v 3 (b) An equation for the sum of the currents leaving the supernode can be written in the form _________ ( ) v 1 + __________ ( ) v 2 + __________ ( ) v 3 + ___________ ( ) = . Fill in each blank in the equation with a single number. v 1 5 + v 1 15 + v 2 20 + v 2 − v 3 10 − 1 = 4 v 1 15 + 3 v 2 20 − v 3 10 − 1 = 0 or 0.2667 v 1 + 0.15 v 2 − 0.1 v 3 − 1 = R 2 V s I s R 1 R 4 R 3 I x /5 I x v 1 v 2 v 3 2. In the circuit below R 1 = 8 Ω , R 2 = 12 Ω , R 3 = 4 Ω , R 4 = 16 Ω and V s = 5V . Using the mesh current...
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## This note was uploaded on 05/01/2010 for the course ECE 300 taught by Professor Watson during the Spring '09 term at Carson-Newman.

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circuits_Test3Solution - Solution of ECE 300 Test 3 F09 1...

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