circuits_Test3Solution

circuits_Test3Solution - Solution of ECE 300 Test 3 F09 1...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Solution of ECE 300 Test 3 F09 1. In the circuit below R 1 = 5 Ω , R 2 = 15 Ω , R 3 = 20 Ω , R 4 = 10 Ω , V s = 20V and I s = 1A . (a) The current I x can be expressed in terms of the node voltages v 1 , v 2 and v 3 . Fill in each blank in the equation with a single number. I x = _________ ( ) v 1 + __________ ( ) v 2 + __________ ( ) v 3 I x = 1 / 5 ( ) v 1 + 1 / 20 ( ) v 2 + ( ) v 3 OR v 3 − v 2 10 = I x / 5 ⇒ I x = ( ) v 1 − 1 / 2 ( ) v 2 + 1 / 2 ( ) v 3 (b) An equation for the sum of the currents leaving the supernode can be written in the form _________ ( ) v 1 + __________ ( ) v 2 + __________ ( ) v 3 + ___________ ( ) = . Fill in each blank in the equation with a single number. v 1 5 + v 1 15 + v 2 20 + v 2 − v 3 10 − 1 = 4 v 1 15 + 3 v 2 20 − v 3 10 − 1 = 0 or 0.2667 v 1 + 0.15 v 2 − 0.1 v 3 − 1 = R 2 V s I s R 1 R 4 R 3 I x /5 I x v 1 v 2 v 3 2. In the circuit below R 1 = 8 Ω , R 2 = 12 Ω , R 3 = 4 Ω , R 4 = 16 Ω and V s = 5V . Using the mesh current...
View Full Document

This note was uploaded on 05/01/2010 for the course ECE 300 taught by Professor Watson during the Spring '09 term at Carson-Newman.

Page1 / 4

circuits_Test3Solution - Solution of ECE 300 Test 3 F09 1...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online