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# Test10Solution - Solution of ECE 300 Test 10 F09 1 Find...

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Unformatted text preview: Solution of ECE 300 Test 10 F09 1. Find numerical values of the constants. (All angles are in degrees.) (a) 5 ∠ 60 ° − 7 ∠− 30 ° = A ∠ B ° 5 ∠ 60 ° − 7 ∠− 30 ° = − 3.562 + j 7.83 = 8.602 ∠ 114.46 (b) 1 − j 2 ( ) 4 ∠ 90 ( ) = A ∠ B ° 1 − j 2 ( ) 4 ∠ 90 ( ) = 8.944 ∠ 26.57 ° (c) 3 + j 4 2 − j 5 = A + jB 3 + j 4 2 − j 5 = − 0.483 + j 0.793 2. With reference to the circuit below, (a) If the impedance of the inductor is A ∠ B ° what are the numerical values of A and B ? Z L = j ω L = j 20 π × 0.4 = j 25.13 Ω = 25.13 ∠ 90 ° Ω (a) If the impedance of the capacitor is A ∠ B ° what are the numerical values of A and B ? Z C = 1 / j ω C = 1 / j 20 π × 250 × 10 − 6 ( ) = − j 63.66 Ω = 63.66 ∠− 90 ° Ω (c) If the impedance of the RLC circuit connected across the current source is A ∠ B ° what are the numerical values of A and B ? Z RLC = R || j ω L + 1 / j ω C ( ) = R j ω L + 1 / j ω C ( ) R + j ω L + 1 / j ω C = 50 25.13 ∠ 90 ° + 63.66 ∠− 90 ° ( ) 50 + 25.13 ∠ 90 ° + 63.66 ∠− 90 ° Z RLC = 50 j 25.13 − j 63.66 ( ) 50 + j 25.13 − j 63.66 = 50 − j 38.53 ( ) 50 − j 38.53 = 30.52 ∠− 52.38 ° (d) Assume that the radian frequency of the current source can be set to any frequency. Assume that the radian frequency of the current source can be set to any frequency....
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## This note was uploaded on 05/01/2010 for the course ECE 300 taught by Professor Watson during the Spring '09 term at Carson-Newman.

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Test10Solution - Solution of ECE 300 Test 10 F09 1 Find...

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