Test5Solution

# Test5Solution - Solution of ECE 300 Test 5 F09 1 In the...

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Solution of ECE 300 Test 5 F09 1. In the circuit below, find the numerical value of V out . V 1 = 3V , V 2 = 5V , R 1 = 10k Ω R 2 = 5k Ω , R f = 20k Ω V out = V 1 R f R 1 + V 2 R f R 2 = R f V 1 R 1 + V 2 R 2 V out = 20,000 3 10000 + 5 5000 = 20,000 6 20000 + 20 20000 = − − 14 ( ) = 14V 2. In the circuit below, find the numerical value of R s . I 1 = 30mA , R 1 = 500 Ω , R f = 4k Ω R L = 1M Ω , V L = 25V V L = I 1 R 1 R f + R s R s 25V = 0.03A × 500 Ω ( ) 4000 Ω + R s R s 25V × R s = 15V 4000 Ω + R s ( ) 10V × R s = 15V × 4000 Ω R s = 6000 Ω R 1 R 2 R f V 1 V 2 V out R f R s I 1 R 1 R L V L

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Solution of ECE 300 Test 5 F09 1. In the circuit below, find the numerical value of V out . V 1 = 3V , V 2 = 5V , R 1 = 10k Ω R 2 = 5k Ω , R f = 40k Ω V out = V 1 R f R 1 + V 2 R f R 2
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## This note was uploaded on 05/01/2010 for the course ECE 300 taught by Professor Watson during the Spring '09 term at Carson-Newman.

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Test5Solution - Solution of ECE 300 Test 5 F09 1 In the...

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