chem lab march

chem lab march - Conclusion I learned to find the...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
Harsimran Sodhi Period 3 3/10/10 The absorption spectrum of the Cobalt (II) Chloride Purpose: The purpose of this lab is to find the absorbance of CoCl2 using the spectrum and wavelengths.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Observations 1. From 400 to 500 wavelengths, the absorbance was increasing. After 500 wavelengths, the absorbance started to decrease again in a decreasing order. 2. At the wavelengths of 500, the absorbance was highest equaling to .700. 3. When we tested the solutions in test tubes, 4ml of .150 M CoCl2 had more morality than the 1 ml. As the Ml decreased the molarity decreased and as the ml of distilled water increased the molarity decreased.
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Conclusion I learned to find the absorbance when using the spectrum and wavelengths. I also learned to find the molarity of a solution. To find the molarity we basically use the cross multiplication using the values. We had no problems in lab, we were safe and almost perfect. We only had 1 Percent error. As we had .098 and the real answer was .099 for the unknown solution (# 1) told by the teacher. I think everything went fluent and no one had any problems. Therefore I cant recommend anything, but I will still recommend to leave the phase of lab as it is....
View Full Document

Page1 / 4

chem lab march - Conclusion I learned to find the...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online