Notes_from_Transport[1]

Notes_from_Transport[1] - U = inulin concentration in...

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General Mechanisms of Reabsorption Apical Basolateral Capillary Trans- cellular Para- cellular
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Reabsorption of Na+, Glucose, HCO 3 - Na+ Na+ + H+ K+ Na+ Glu Glu Na+ HCO 3 - H 2 O + CO 2 CO 2 H 2 O + CO 2 H++ HCO 3 - Na+ Lumen Epithelium ECF ATP H 2 CO 3 CA [Cl-]=140 mM [Cl-]=105 mM
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Secretion of H+ Ions Lumen ECF H+ Secretion in Prox. Tubule (see previous figure, H+ concurrent with reabsorption of NaHCO 3 ) Cl- H+ HCO 3 - CO 2 H 2 O ATP OH- Cl- H+ H+ K+ ATP K+
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Lumen Epithelium ECF Na+ K+ ATP K+ OAT OCT Anionic drugs (e.g., diuretics, penicillins) Cationic drugs (e.g., nicotine) Secretion of K+ Ions & Xenobiotics
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Excretion & Clearance Excretion Rate = Filtration Rate + Secretion Rate – Reabsorption Rate Inulin is not secreted or absorbed, so Excretion Rate = Filtration Rate. If V = rate of urine formation (ml/min)
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Unformatted text preview: U = inulin concentration in urine (mg/ml) Then, rate of inulin excretion = V × U (mg/min) Rate of filtration of inulin = GFR (ml/min) × [inulin] plasma (mg/ml) Rate of excretion = rate of filtration, so V × U = GFR × [inulin] plasma Solve for GFR = (V × U) / [inulin] plasma If V = 2 ml/min, U = 30 mg/ml, and [inulin] plasma = 0.6 mg/ml, then Renal Handling of Solutes Micturition Reflex Full Bladder 1. Stretch receptors activated 2. Parasympathetic stimulation of muscle contraction; inhibition of MNs to external sphincter muscle 3. Contractions increase P, forces internal sphincter open, urination...
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