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Unformatted text preview: Chapter 4 Answers 1. (a) The predicted average test score is 520 4 5 82 22 392 36 TestScore = .  . = . (b)The predicted change in the classroom average test score is ( 5 82 19) ( 5 82 23) 23 28 TestScore =  .  . = . (c) Using the formula for in Equation (4.8), we know the sample average of the test scores across the 100 classrooms is 1 520 4 5 82 21 4 395 85 TestScore CS = + = .  . . = . . (d)Use the formula for the standard error of the regression (SER) in Equation (4.19) to get the sum of squared residuals: 2 2 ( 2) (100 2) 11 5 12961 SSR n SER = = . = . Use the formula for 2 R in Equation (4.16) to get the total sum of squares: 2 2 12961 13044 1 1 0 08 SSR TSS R = = = . . The sample variance is 2 Y s = TSS 13044 1 99 131 8. n = = . Thus, standard deviation is 2 11 5. Y Y s s = = . 2. The sample size 200. n = The estimated regression equation is 2 (2 15) 99 41 (0 31) 3 94 0 81 SER 10 2 Weight Height R = . . + . . , = . , = . . (a) Substituting 70, 65, and 74 Height = inches into the equation, the predicted weights are 176.39, 156.69, and 192.15 pounds....
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This note was uploaded on 05/03/2010 for the course ECON 303 taught by Professor Grant during the Spring '10 term at Lewis and Clark Community College.
 Spring '10
 Grant
 Econometrics

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