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Problem 1.8 EC - P roblem 1.8 LP L EXTRA CRED I T R I K...

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Problem 1.8 LPL EXTRA CREDIT RIK SENGUPTA 1. We would have the following atomic sentences: i. GaveScruffy(claire, claire) ii. GaveScruffy(max, claire) iii. GaveScruffy(claire, max) iv. GaveScruffy(max, max) v. GaveCarl(claire, claire) vi. GaveCarl(max, claire) vii.GaveCarl(claire, max) viii. GaveCarl(max, max) 2. The number of possible sentences can be easily determined. Since there are three variables x , y , and z , and each can take any of four values max, claire, scruffy and carl (repetitions allowed), the number of permutations possible is 4 3 = 64. To complete the answer, we would have the following atomic sentences: i. Gave(max, max, max) ii. Gave(max, max, claire) iii. Gave(max, max, scruffy) iv. Gave(max, max, carl) v. Gave(max, claire, max) vi. Gave(max, claire, claire) vii.Gave(max, claire, scruffy)
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viii. Gave(max, claire, carl) ix. Gave(max, scruffy, max) x. Gave(max, scruffy, claire) xi. Gave(max, scruffy, scruffy) xii.Gave(max, scruffy, carl) xiii. Gave(max, carl, max) xiv.Gave(max, carl, claire) xv. Gave(max, carl, scruffy) xvi. Gave(max, carl, carl) xvii.
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