ST 558 Homework 9

ST 558 Homework 9 - Kelly Harrison ST 558 Assignment 9...

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Kelly Harrison ST 558 Assignment 9 PROBLEM 1 96%   z = 1.75 f8e5 ±  z σ / n = 780  ±  1.75(40)/ 30 = (767.2, 792.8). PROBLEM 2 a) n = 50,  f8e5 x = 174.5, s = 6.9 98% and df = 50 – 1 = 49   t = 2.407 f8e5 ±  ts/ n = 174.5  ±  2.405(6.9)/ 50 = (172.15, 176.85). b) I would expect the error to be at most (176.85-172.15)/2 = 2.35. PROBLEM 3 n = 20,  f8e5 x = 11.3, s = 2.45 95% and df = 20 – 1 = 19   t = 2.093 f8e5 ±  ts/ n = 11.3  ±  2.093(2.45)/ 20 = (10.15, 12.45). PROBLEM 4 n = 10, f8e5 x = 230, s = 15 99% and df = 9   t = 3.250 f8e5 ±  ts/ n = 230  ±  3.250(15)/ 10 = (214.58, 245.42). PROBLEM 5 Ho:  μ  = 162.5 H1:  μ    162.5 Reject Ho if p-value < .05. z = ( f8e5 x –  μ )/( σ / n) = (165.2-162.5)/(6.9/ 50) = 2.77
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P-value = 2P(z > 2.77) = 2(.0028) = .0056 Since p-value < .05 then reject Ho.
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This note was uploaded on 05/06/2010 for the course ST 558 taught by Professor Staff during the Spring '08 term at NMT.

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ST 558 Homework 9 - Kelly Harrison ST 558 Assignment 9...

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