10. Fig. 3043(b) demonstrates that
/
dB dt
(the slope of that line) is 0.003 T/s.
Thus, in
absolute value, Faraday’s law becomes
(
)
B
d
d BA
dB
A
dt
dt
dt
ε
Φ
= −
= −
= −
where
A
= 8
×
10
−
4
m
2
.
We related the induced emf to resistance and current using Ohm’s
law.
The current is estimated from Fig. 3043(c) to be
i
=
/
dq dt
=
0.002 A (the slope of
that line).
Therefore, the resistance of the loop is
4
2



/

(8.0
10
m
)(0.0030 T/s)
0.0012
0.0020 A
A dB dt
R
i
i
ε
−
×
=
=
=
=
Ω
.
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