CH06pt2 - 5 Competitive Box 6-2 v = V max [ S ] K m + [ S ]...

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Unformatted text preview: 5 Competitive Box 6-2 v = V max [ S ] K m + [ S ] = 1 + [ I ] K i Box 6-2 Uncompetitive Box 6-2 Mixed v ( mol/min) 0.011 0.025 0.047 0.08 0.13 0.19 0.27 0.28 0.29 [S](x 10-5 M) 0.1 0.25 0.5 1.0 2.0 5.0 25.0 50.0 100.0 The following kinetic data were obtained for your enzyme: Plot the substrate-velocity data: Calculate (dont estimate) K m and V max for the enzyme. Take reciprocal of data in previous table, then plot 1/v vs 1/[S]: Equation of resulting line: y = (8.79 x 10-5 )x + 3.58 (y = m x + b ) y-int = 1/V max = 3.58 V max = 0.28 slope = K m /V max = 8.79 x 10-5 K m = (0.28)( 8.79 x 10-5 ) = 2.46 x 10-5 M (~25 M) Can also directly calculate K m from x-int: x-int = -0.41 = -1/K m = 2.45 x 10-5 M (Ping-Pong) 6 Enzymes (Ch. 6) 2. Mechanisms Recall the extraordinary enhancements of rate which enzymes produce: generally a factor of 10 6 to 10 17 . Factors which contribute to catalytic efficiency of enzymes: 1. Binding energy 2. General acid-base catalysis 3. Covalent catalysis...
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CH06pt2 - 5 Competitive Box 6-2 v = V max [ S ] K m + [ S ]...

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