10_1

Materials Science and Engineering: An Introduction

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
227 CHAPTER 10 PHASE TRANSFORMATIONS IN METALS PROBLEM SOLUTIONS 10.1 The two stages involved in the formation of particles of a new phase are nucleation and growth . The nucleation process involves the formation of normally very small particles of the new phase(s) which are stable and capable of continued growth. The growth stage is simply the increase in size of the new phase particles. 10.2 This problem calls for us to compute the length of time required for a reaction to go to 99% completion. It first becomes necessary to solve for the parameter k in Equation (10.1). Rearrangement of this equation leads to k = - ln(1 - y)
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: t n = - ln(1 - 0.5) (100 s) 1.7 = 2.76 x 10-4 Now, solving for the time to go to 99% completion t = [ ]- ln(1 - y) k 1/n =      - ln(1 - 0.99) 2.76 x 10-4 1/1.7 = 305 s 10.3 This problem asks that we compute the rate of some reaction given the values of n and k in Equation (10.1). Since the reaction rate is defined by Equation (10.2), it is first necessary to determine t 0.5 , or the time necessary for the reaction to reach y = 0.5. Solving for t 0.5 from Equation (10.1) leads to t 0.5 = [ ]- ln(1 - 0.5) k 1/n =      - ln(1 - 0.5) 7 x 10-3 1/3 = 4.63 s...
View Full Document

This document was uploaded on 05/04/2010.

Ask a homework question - tutors are online