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**Unformatted text preview: **t n = - ln(1 - 0.5) (100 s) 1.7 = 2.76 x 10-4 Now, solving for the time to go to 99% completion t = [ ]- ln(1 - y) k 1/n = - ln(1 - 0.99) 2.76 x 10-4 1/1.7 = 305 s 10.3 This problem asks that we compute the rate of some reaction given the values of n and k in Equation (10.1). Since the reaction rate is defined by Equation (10.2), it is first necessary to determine t 0.5 , or the time necessary for the reaction to reach y = 0.5. Solving for t 0.5 from Equation (10.1) leads to t 0.5 = [ ]- ln(1 - 0.5) k 1/n = - ln(1 - 0.5) 7 x 10-3 1/3 = 4.63 s...

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