10_4

# Materials Science and Engineering: An Introduction

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230 Solving these two expressions simultaneously for n and k yields n = 2.112 and k = 9.75 x 10 -4 . Now it becomes necessary to solve for y when t = 22.8 min. Application of Equation (10.1) leads to y = 1 - exp ( ) - kt n = 1 - exp [ ] - (9.75 x 10 -4 )(22.8 min) 2.112 = 0.51 10.7 This problem asks us to consider the percent recrystallized versus logarithm of time curves for copper shown in Figure 10.2.
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Unformatted text preview: (a) The rates at the different temperatures are determined using Equation (10.2), which rates are tabulated below: Temperature ( ° C) Rate (min)-1 135 0.105 119 4.4 x 10-2 113 2.9 x 10-2 102 1.25 x 10-2 88 4.2 x 10-3 43 3.8 x 10-5 (b) These data are plotted below. 0.0032 0.0030 0.0028 0.0026 0.0024-12-10-8-6-4-2 1/T (1/K) ln Rate (1/min)...
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## This document was uploaded on 05/04/2010.

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