This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Math 136 Assignment 7 Solutions 1. Show the each of the following sets form a basis for the subspace that they span, and determine the coordinates of ~x and ~ y with respect to the basis. a) { (1 , 1 , , 1 , 0) , (1 , , 2 , 1 , 1) , (0 , , 1 , 1 , 3) } ; ~x = (2 , 2 , 5 , 1 , 5), ~ y = ( 1 , 3 , 3 , 2 , 1). Consider 0 = c 1 (1 , 1 , , 1 , 0) + c 2 (1 , , 2 , 1 , 1) + c 3 ((0 , , 1 , 1 , 3) = ( c 1 + c 2 ,c 1 , 2 c 2 + c 3 ,c 1 + c 2 + c 3 ,c 2 + 3 c 3 ) We rowreduce the coefficient matrix to get 1 1 0 1 0 0 0 2 1 1 1 1 0 1 3 ∼ 1 0 0 0 1 0 0 0 1 0 0 0 0 0 0 . Thus, the only solution is c 1 = c 2 = c 3 = 0 so the set of vectors is linearly independent and so the vectors in B form a basis for the subspace which they span. The coordinates of ~x with respect to B and the coordinates of ~ y with respect to B are determined by rowreducing the augmented systems c 1 (1 , 1 , , 1 , 0) + c 2 (1 , , 2 , 1 , 1) + c 3 (0 , , 1 , 1 , 3) = (2 , 2 , 5 , 1 , 5) d 1 (1 , 1 , , 1 , 0) + d 2 (1 , , 2 , 1 , 1) + d 3 (0 , , 1 , 1 , 3) = ( 1 , 3 , 3 , 2 , 1) . We make one doubly augmented matrix and rowreduce to get 1 1 0 2 1 1 0 0 2 3 0 2 1 5 3 1 1 1 1 2 0 1 3 5 1 ∼ 1 0 0 2 3 0 1 0 4 2 0 0 1 3 1 0 0 0 0 0 0 Thus [ ~x ] B = c 1 c 2 c 3 =  2 4 3 and [ ~ y ] B = d 1 d 2 d 3 =  3 2 1 . b) 1 1 1 0 , 0 1 1 1 , 2 1 ; ~x = 0 1 1 2 , ~ y = 4 1 1 4 ....
View
Full
Document
This note was uploaded on 05/04/2010 for the course MATH 136 taught by Professor All during the Spring '08 term at Waterloo.
 Spring '08
 All
 Linear Algebra, Algebra, Sets

Click to edit the document details